我如何在困难的数组中进行总计答案

【问题标题】：How i can make Totals in difficult array我如何在困难的数组中进行总计
【发布时间】：2021-06-04 18:03:43
【问题描述】：

我需要不同任务的帮助（对我来说不同，因为我是 JS 的新手）我有数组：

let results = [
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":40271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":4815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    },
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":10271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":1815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    }
]

我必须有这样的结果：

let result = [
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":X1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":X2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ],
        "total":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":X1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":X2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    },
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":Y1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":Y2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ],
        "total":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":Y1+X1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":Y2+X2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    }
]

我没有任何想法，结果可能超过 2。在每一步上，我必须有当前总步数 + 之前的步数

【问题讨论】：

“当前总步数+之前的步数”是什么意思？看起来您只是从results 属性复制到total 属性，它没有添加任何内容。
在第一把上我投入总时间：x1 在第二步我投入时间：x2+x1 在第三我必须投入时间 = x3+x2+x1（x1 = 第一圈时间，x2= ti,e 在第二圈.....）

标签： javascript node.js arrays mapreduce

【解决方案1】：

使用数组来保存累计次数。然后您可以通过复制相应的results 数组并将time 属性替换为累计次数来创建time 数组。

let results = [
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":40271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":4815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    },
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":10271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":1815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    }
]


let total_time = Array(results[0].results.length).fill(0);

let result = results.map(res => {
  let time = res.results.map((r, i) => {
    total_time[i] += r.time;
    return { ...r, time: total_time[i]
    }
  });
  return { ...res, time: time
  };
});

console.log(result);

【讨论】：

【解决方案2】：

首先定义函数：

function reducer(acc, item) {
  let totals = !acc.length ? [...item.results] : [
    {...item.results[0], time: item.results[0].time + acc[acc.length - 1].results[0].time},
    {...item.results[1], time: item.results[1].time + acc[acc.length - 1].results[1].time},
  ];
  acc.push({...item, totals});
  return acc;
}

然后像这样使用它：

let resultWithTotals = results.reduce(reducer, []);

【讨论】：

【解决方案3】：

result[0]["total"] = result[0].results; 

for (let i = 1; i < result.length; i++) {
    let newTotal = JSON.parse(JSON.stringify(result[i - 1]["total"]));
    for (let j = 0; newTotal && j < newTotal.length; j++) {
        newTotal[j].time += result[i].results[j].time; // assuming your X1, Y1, X2, Y2 are numbers
    }
    result[i]["total"] = newTotal;
}

console.log(result);

【讨论】：

【解决方案4】：

你可以这样做：

      results.forEach((ele,index)=>{
let total = results[index].results;
for(let i = 0;i<=index;i++){
results[index].results.forEach((element,index)=>{
total[index].time += element.time;
})

}
results[index].total=total;
    })

我想这应该可行！

更新：

上面的代码中存在参考问题，解决方法如下：

var resultsCopy = JSON.parse(JSON.stringify(results));
resultsCopy.forEach((ele,index)=>{
let total = resultsCopy[index].results;
for(let i = 0;i<=index;i++){
resultsCopy[index].results.forEach((element,index)=>{
total[index].time += element.time;
})

}
results[index].total=total;
    })

【讨论】：

谢谢）我尝试过这样的事情，但在这两种情况下我都有：[圆形对象数组]
嘿，看看这个，现在有参考问题，我现在修复它工作正常