Telethon 事件不会获取特定用户的事件

Question

所以我已经在这个脚本上工作了几天了，该脚本似乎可以正确运行而没有出现任何错误，但问题是我的脚本是获取特定用户的状态更改，而不是脚本打印每当我的联系人中的任何人改变他们的状态时，我都会对我自己产生影响。 请问，有人认为他可以帮助我吗？我已经坚持太久了，我真的很绝望让这个脚本有效..

顺便说一句，我添加 print(client.user_id) 只是为了看看它是否有效，并且我收到了我的联系人中任何人的用户 ID，他们采取了某种行动。

from telethon.tl.types import UserStatusOffline
from telethon.sync import TelegramClient
from telethon import events
from datetime import datetime
import time

### Client Side ###

target = ""
phone = "+"
api_id = 
api_hash = ""
client = TelegramClient(phone, api_id, api_hash)
client.start()
if client.is_user_authorized():
    print(f"Session started at : {datetime.now()}")
    time.sleep(2)
    print("Logging in to Telegram complete.")
    time.sleep(2)
else:
    client.send_code_request(phone)
    client.sign_in(phone, input('Enter the code: '))
print(f"Started listening to {target}'s status...")
time.sleep(2)
target_id = client.get_peer_id(target)
print(f"{target}'s User ID is : {target_id}")
time.sleep(2)

############################################
# First status check to see rather         #
# the user is correctly online or not      #
# once it prints hes correct statement     #
# global value will be changed so it wont  #
# be printed again and again.              #
############################################

first_msg = False
async def first_con():
    if first_msg == False:
        account = await client.get_entity(target)
        if isinstance(account.status, UserStatusOffline):
            print(f"{target} is correctly Offline.")
            first_msg = True
        else:
            print(f"{target} is correctly Online.")
            first_msg = True
    else:
        print("Something went wrong checking correct status.")
        
            
##################EVENTS####################
# Only events thats occurred after script  #
# first run will pop up with prints !      #
# Every event that doesn't come from the   #
# target gets as "event from username"     #
############################################

@client.on(events.UserUpdate())
async def handler(event):
    await first_con()
    time.sleep(2)
    if event.user_id == target_id:
        if event.online:
            print(f"{target} went Online at : {datetime.now()}")
        elif event.recently:
            print(f"{target} was recently online at : {datetime.now()}")
        elif event.typing:
            print(f"{target} typed a message at : {datetime.now()}")
        else:
            print("Sorry there was an error.")
    else:
        #print("Event from non-intersting user.") debugging propuses only
client.run_until_disconnected()

Answer 1

让我们放大代码：

@client.on(events.UserUpdate())
async def handler(event):
    x = await client.get_entity(target)
    target_id = x.id
    event.input_user = target_id
    if event.input_user == target_id:

让我们把它拆开：

    event.input_user = target_id
    if event.input_user == target_id:

让我们给它起不同的名字。 event.input_user 将是 foo 和 target_id 将是 bar：

    foo = bar
    if foo == bar:

您刚刚为第一个变量赋值，然后将第一个变量与相同的值进行比较。当然，对于任何 foo 和 bar 值，这始终是 True。

修改event 通常是一个坏主意，我不确定您的意图是什么，但在我看来，您应该缓存 integer ID，然后比较它而不是每次都调用get_entity（因为input_user 是InputPeerUser 并且不会与User 比较，这就是为什么我猜你尝试了奇怪的分配）：

target_id = client.get_peer_id(target)


@client.on(events.UserUpdate)
async def handler(event):
    if event.user_id == target_id:
        ...

这种方式最多只进行一次调用，并且您比较快速的整数。请务必查看documentation on UserUpdate 了解更多信息。