如何在 postgresql 的 jsonb 列中搜索

Question

我基本上有一个包含 jsonb 类型列的 postgresql 表。 json数据是这样的

{
  "personal": {  
    {
       "gender":"male",
       "contact":{
          "home":{
             "email":"ceo@home.me",
             "phone_number":"5551234"
          },
          "work":{
             "email":"ceo@work.id",
             "phone_number":"5551111"
          }
       },
       "religion":"other",
       "languages":[
          "English",
          "Xen"
       ],
       "last_name":"Eeo",
       "birth_date":"1945-07-28",
       "first_name":"Cee",
       "nationality":"Martian",
       "marital_status":"married"
    }
  }
}

我想获取所有具有“火星人”和“人族”国籍的人......在我的 postgresql 命令行中这是可行的

select employees->'personal'->'contact'->'work'->'email' 
from employees 
where employees->'personal' @> '{"nationality":"Martian"}' 
   or employees->'personal' @> '{"nationality":"Terran"}'

这可行.. 但它很丑.. 我想运行这样的东西：

select employees->'personal'->'contact'->'work'->'email' 
from employees 
where employees->'personal'->'nationality' in ('Martian','Terran')

但我收到这样的格式错误：

DETAIL:  Token "Martian" is invalid.
CONTEXT:  JSON data, line 1: Martian

Answer 1

您必须使用“get value as text”操作符->> 来实现这一点：

select employees->'personal'->'contact'->'work'->>'email' 
from employees 
where employees->'personal'->>'nationality' in ('Martian','Terran')

我还将它添加到获取电子邮件中，因为我假设您希望它作为文本。

请注意，转换为文本 (employees->'personal'->'nationality')::text 不起作用，因为它不仅返回值，而且将 json 转换为文本，在本例中为 "Martian"，包括引号。

Answer 2

使用->> operator:

select employees->'personal'->'contact'->'work'->'email' 
from employees 
where employees->'personal'->>'nationality' in ('Martian','Terran')