查找最新的 3 条状态相同的记录

Question

我需要为每个具有特定“失败”状态的用户查找最新的 3 条记录。起初这似乎很容易，但我似乎无法做到。

所以在一个表中：

ID         Date            Status
1          2017-01-01     Fail
1          2017-01-02     Fail
1          2017-02-04     Fail
1          2015-03-21     Pass
1          2014-02-19     Fail
1          2016-10-23     Pass
2          2017-01-01     Fail
2          2017-01-02     Pass
2          2017-02-04     Fail
2          2016-10-23     Fail

我希望返回 ID 1，因为最近的 3 条记录失败，但不是 ID 2，因为它们在三个失败中都有通过。每个用户可能有任意数量的通过和失败记录。有成千上万种不同的 ID

到目前为止，我已经尝试使用 ROW_NUMBER() 对尝试进行排序，但想不出一种方法来确保最新的三个结果都具有相同的 Fail 状态。

预期结果

ID Latest Fail Date    Count
1  2017-02-04          3

Answer 1

不妨试试这样的：

WITH cte
AS 
(

SELECT id,
       date,
       status,
      ROW_NUMBER () OVER (PARTITION BY id ORDER BY date DESC) row
FROM #table


),cte2
AS
(

SELECT  id, max(date) as date, count(*) AS count
FROM cte
WHERE status = 'fail'
AND row <= 3
GROUP BY id
)

SELECT id,
       date AS latest_fail,
       count
FROM cte2
WHERE count = 3

Answer 2

检查一下。

演示：Here

with CTE as
(
 select *,ROW_NUMBER () over( partition by id order by date desc) rnk 
 from temp
 where Status ='Fail'
)
 select top 1 ID,max(DATE) as Latest_Fail_Date ,COUNT(rnk) as count 
 from CTE where rnk <=3
 group by ID

输出：

Answer 3

我认为你可以使用cross apply：

select i.id
from (select distinct id from t) i cross apply
     (select sum(case when t.status = 'Fail' then 1 else 0 end) as numFails
      from (select top 3 t.*
            from t
            where t.id = i.id
            order by date desc
           ) ti
      ) ti
where numFails = 3;

注意：您可能有一个包含所有 id 的表。如果是这样，您可以使用它而不是 select distinct 子查询。

或者，类似地：

select i.id
from (select distinct id from t) i cross apply
     (select top 3 t.*
      from t
      where t.id = i.id
      order by date desc
      ) ti
group by i.id
having min(ti.status) = 'Fail' and max(ti.status) = 'Fail' and
       count(*) = 3;

Answer 4

给你：

declare @numOfTries int = 3;

with fails_nums as 
(
       select *, row_number() over (partition by ID order by [Date] desc) as rn
       from #fails
)
select ID, max([Date]) [Date], count(*) as [count]
from fails_nums fn1
where fn1.rn <= @numOftries
group by ID
having count(case when [Status]='Fail' then [Status] end) = @numOfTries

Example here