【问题标题】:Oracle SQL Join and Count CaseOracle SQL 连接和计数案例
【发布时间】:2018-06-13 19:47:31
【问题描述】:

我有一门课程,学生按年份注册,他们有出勤记录,我需要从每年的总注册人数中知道有多少人实际参加了该课程,实现该目标所需的 SQL 查询是什么?

预期输出:

YEAR COURSE ENROLED ATTENDED
---- ------ ------- --------
2017 IT           3        2
2018 IT           2        0 

Oracle 脚本示例:

--
DROP TABLE ATTENDANCE;
DROP TABLE ENROLMENT;
DROP TABLE STUDENT;
DROP TABLE COURSE;
--
CREATE TABLE COURSE (ID VARCHAR2(1), NAME VARCHAR2(20), PRIMARY KEY(ID));
CREATE TABLE STUDENT (ID VARCHAR2(1), NAME VARCHAR2(20), PRIMARY KEY(ID));
CREATE TABLE ENROLMENT (ID VARCHAR2(1), COURSE_ID VARCHAR2(1), STUDENT_ID VARCHAR2(1), YEAR VARCHAR2(4), PRIMARY KEY(COURSE_ID, STUDENT_ID, YEAR));
CREATE TABLE ATTENDANCE (ENROLMENT_ID VARCHAR2(1), PRIMARY KEY(ENROLMENT_ID));
--
INSERT INTO COURSE VALUES('1', 'IT');
INSERT INTO STUDENT VALUES('1', 'John');
INSERT INTO STUDENT VALUES('2', 'Mary');
INSERT INTO STUDENT VALUES('3', 'Peter');
INSERT INTO ENROLMENT VALUES('1', '1', '1', '2017');
INSERT INTO ENROLMENT VALUES('2', '1', '2', '2017');
INSERT INTO ENROLMENT VALUES('3', '1', '3', '2017');
INSERT INTO ENROLMENT VALUES('4', '1', '1', '2018');
INSERT INTO ENROLMENT VALUES('5', '1', '2', '2018');
INSERT INTO ATTENDANCE VALUES('1');
INSERT INTO ATTENDANCE VALUES('2');
COMMIT;
--

【问题讨论】:

  • 从标题看起来像oracle
  • 是的,数据库是Oracle
  • 选择 E.YEAR、C.NAME、COUNT(S.ID) 从课程 C 注册 左加入注册 E 在 C.ID = E.COURSE_ID 左加入学生 S 在 E.STUDENT_ID = S。 ID GROUP BY E.YEAR, C.NAME ORDER BY E.YEAR, C.NAME;

标签: sql oracle


【解决方案1】:

怎么样:

select e.year, c.name, 
    count(distinct s.id) as enroled, 
    count(distinct a.enrolment_id) as attended
  from enrolment e
  join course c on e.course_id = c.id
  left join student s on s.id = e.student_id
  left join attendance a on a.enrolment_id = e.id
  group by e.year, c.name

结果:

year  name  enroled  attended
----  ----  -------  -----
2017  IT    3        2
2018  IT    2        0

【讨论】:

  • 就是这样!非常感谢,我的sql太生疏了,,,
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