【问题标题】:unable to give schema name as input while creating dataframe from hive table in scala从 scala 中的 hive 表创建数据框时无法提供模式名称作为输入
【发布时间】:2015-12-22 09:44:45
【问题描述】:

我正在尝试从 clickstream_db 架构中存在的现有配置单元表创建数据框。

val ganulardataframe=hc.table("clickstream_db.granulartable");

它给出了一个错误:

org.apache.spark.sql.catalyst.analysis.NoSuchTableException
        at org.apache.spark.sql.hive.client.ClientInterface$$anonfun$getTable$1.apply(ClientInterface.scala:112)
        at org.apache.spark.sql.hive.client.ClientInterface$$anonfun$getTable$1.apply(ClientInterface.scala:112)
        at scala.Option.getOrElse(Option.scala:120)
        at org.apache.spark.sql.hive.client.ClientInterface$class.getTable(ClientInterface.scala:112)
        at org.apache.spark.sql.hive.client.ClientWrapper.getTable(ClientWrapper.scala:61)
        at org.apache.spark.sql.hive.HiveMetastoreCatalog.lookupRelation(HiveMetastoreCatalog.scala:227)
        at org.apache.spark.sql.hive.HiveContext$$anon$2.org$apache$spark$sql$catalyst$analysis$OverrideCatalog$$super$lookupRelation(HiveContext.scala:373)
        at org.apache.spark.sql.catalyst.analysis.OverrideCatalog$$anonfun$lookupRelation$3.apply(Catalog.scala:165)
        at org.apache.spark.sql.catalyst.analysis.OverrideCatalog$$anonfun$lookupRelation$3.apply(Catalog.scala:165)
        at scala.Option.getOrElse(Option.scala:120)
        at org.apache.spark.sql.catalyst.analysis.OverrideCatalog$class.lookupRelation(Catalog.scala:165)
        at org.apache.spark.sql.hive.HiveContext$$anon$2.lookupRelation(HiveContext.scala:373)
        at org.apache.spark.sql.SQLContext.table(SQLContext.scala:765)
        at $iwC$$iwC$$iwC$$iwC$$iwC$$iwC$$iwC$$iwC.<init>(<console>:23)
        at $iwC$$iwC$$iwC$$iwC$$iwC$$iwC$$iwC.<init>(<console>:28)
        at $iwC$$iwC$$iwC$$iwC$$iwC$$iwC.<init>(<console>:30)
        at $iwC$$iwC$$iwC$$iwC$$iwC.<init>(<console>:32)
        at $iwC$$iwC$$iwC$$iwC.<init>(<console>:34)
        at $iwC$$iwC$$iwC.<init>(<console>:36)
        at $iwC$$iwC.<init>(<console>:38)
        at $iwC.<init>(<console>:40)
        at <init>(<console>:42)
        at .<init>(<console>:46)
        at .<clinit>(<console>)
        at .<init>(<console>:7)
        at .<clinit>(<console>)
        at $print(<console>)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
        at java.lang.reflect.Method.invoke(Method.java:497)
        at org.apache.spark.repl.SparkIMain$ReadEvalPrint.call(SparkIMain.scala:1065)
        at org.apache.spark.repl.SparkIMain$Request.loadAndRun(SparkIMain.scala:1338)
        at org.apache.spark.repl.SparkIMain.loadAndRunReq$1(SparkIMain.scala:840)
        at org.apache.spark.repl.SparkIMain.interpret(SparkIMain.scala:871)
        at org.apache.spark.repl.SparkIMain.interpret(SparkIMain.scala:819)
        at org.apache.spark.repl.SparkILoop.reallyInterpret$1(SparkILoop.scala:857)
        at org.apache.spark.repl.SparkILoop.interpretStartingWith(SparkILoop.scala:902)
        at org.apache.spark.repl.SparkILoop.command(SparkILoop.scala:814)
        at org.apache.spark.repl.SparkILoop.processLine$1(SparkILoop.scala:657)
        at org.apache.spark.repl.SparkILoop.innerLoop$1(SparkILoop.scala:665)
        at org.apache.spark.repl.SparkILoop.org$apache$spark$repl$SparkILoop$$loop(SparkILoop.scala:670)
        at org.apache.spark.repl.SparkILoop$$anonfun$org$apache$spark$repl$SparkILoop$$process$1.apply$mcZ$sp(SparkILoop.scala:997)
        at org.apache.spark.repl.SparkILoop$$anonfun$org$apache$spark$repl$SparkILoop$$process$1.apply(SparkILoop.scala:945)
        at org.apache.spark.repl.SparkILoop$$anonfun$org$apache$spark$repl$SparkILoop$$process$1.apply(SparkILoop.scala:945)
        at scala.tools.nsc.util.ScalaClassLoader$.savingContextLoader(ScalaClassLoader.scala:135)
        at org.apache.spark.repl.SparkILoop.org$apache$spark$repl$SparkILoop$$process(SparkILoop.scala:945)
        at org.apache.spark.repl.SparkILoop.process(SparkILoop.scala:1059)
        at org.apache.spark.repl.Main$.main(Main.scala:31)
        at org.apache.spark.repl.Main.main(Main.scala)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
        at java.lang.reflect.Method.invoke(Method.java:497)
        at org.apache.spark.deploy.SparkSubmit$.org$apache$spark$deploy$SparkSubmit$$runMain(SparkSubmit.scala:665)
        at org.apache.spark.deploy.SparkSubmit$.doRunMain$1(SparkSubmit.scala:170)
        at org.apache.spark.deploy.SparkSubmit$.submit(SparkSubmit.scala:193)
        at org.apache.spark.deploy.SparkSubmit$.main(SparkSubmit.scala:112)
        at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)

如果我将granulartable 作为输入,它将在default 架构中查找此表。

val ganulardataframe=hc.table("granulartable");

我能想到的一个解决方案是在默认数据库中创建同一个表并从中创建数据框。

有没有办法为“表”函数提供模式名称?

谢谢。

【问题讨论】:

    标签: scala hadoop apache-spark hive


    【解决方案1】:

    试试这个,应该可以的

    val l=hc.sql("select * from clickstream_db.granulartable");
    

    使用sql 代替table 并使用sql 查询获取数据。

    【讨论】:

      【解决方案2】:
      hc.sql("use clickstream_db");
      

      默认情况下,hive 将使用默认数据库。我们应该将其更改为您要使用的特定数据库。

      val ganulardataframe=hc.table("granulartable");
      

      【讨论】:

        猜你喜欢
        • 1970-01-01
        • 1970-01-01
        • 1970-01-01
        • 1970-01-01
        • 2021-08-13
        • 1970-01-01
        • 1970-01-01
        • 1970-01-01
        • 1970-01-01
        相关资源
        最近更新 更多