mysql在where子句中使用逻辑+无效使用组函数答案

【问题标题】：mysql use logic in where clause + invalid use of group functionmysql在where子句中使用逻辑+无效使用组函数
【发布时间】：2012-12-21 08:05:44
【问题描述】：

我有下面的 mysql 查询输出下面的图像：

select
  v.invoicenumber,
  v.invoicedate,
  v.haulier,
  v.transporttype,
  count(v.loadnumber) as totalloads,
  sum(v.cost) as totalcost, 
  concat(SUM(if(invoiceapproved = 'yes', 1, 0)),' / ',count(v.loadnumber)) AS count,  SUM(if(invoiceapproved = 'yes', 1, 0)) as approved
from v2loads v  
  where v.invoiced='yes'   
  group by invoicenumber

此查询执行 100%。

我想要做的是过滤掉计数为 100% 的任何行/数据。在示例输出中，我想过滤掉发票 16，因为它是 2/2 和 100%。所以在哪里

 count(v.loadnumber) <> SUM(if(invoiceapproved = 'yes', 1, 0))

如果我将此逻辑添加到 where 子句中，它会因错误无效使用组函数而失败。所以下面的代码不起作用：

select v.invoicenumber,
  v.invoicedate,
  v.haulier,
  v.transporttype,
  count(v.loadnumber) as totalloads,
  sum(v.cost) as totalcost, 
  concat(SUM(if(invoiceapproved = 'yes', 1, 0)),' / ',count(v.loadnumber)) AS count, 
  SUM(if(invoiceapproved = 'yes', 1, 0)) as approved 
from v2loads v  
  where v.invoiced='yes' and 
  (count(v.loadnumber))<>(SUM(if(invoiceapproved = 'yes', 1, 0)))  
  group by invoicenumber

我收到以下错误：

错误是#1111 - 组函数的使用无效。

一如既往地感谢任何建议。

【问题讨论】：

标签： mysql sql logic where

【解决方案1】：

你可以这样做：

SELECT 
  *,
  CONCAT(approved, ' / ', totalloads) AS count, 
FROM
(
    SELECT
      v.invoicenumber,
      v.invoicedate,
      v.haulier,
      v.transporttype,
      COUNT(v.loadnumber)                    AS totalloads,
      SUM(v.cost)                            AS totalcost, 
      SUM(if(invoiceapproved = 'yes', 1, 0)) As approved 
    FROM v2loads v  
    WHERE v.invoiced='yes'
    GROUP BY invoicenumber
) t
WHERE totalloads <> approved;

【讨论】：

太棒了，是的，你是对的，从没想过嵌套它。谢谢马哈茂德。

【解决方案2】：

select v.invoicenumber,
v.invoicedate,
v.haulier,
v.transporttype,
count(v.loadnumber) as totalloads,
sum(v.cost) as totalcost, 
concat(SUM(if(invoiceapproved = 'yes', 1, 0)),' / ',count(v.loadnumber)) AS count,
SUM(if(invoiceapproved = 'yes', 1, 0)) as approved  
from v2loads v 
where v.invoiced='yes'
group by invoicenumber 
having (count(v.loadnumber))<>(SUM(if(invoiceapproved = 'yes', 1, 0)))

【讨论】：