两列之间的Oracle SQL比较？

Question

我正在尝试在两列之间进行比较，以找出它们序列中的不匹配。

Column_A 和 Column_B 具有 char 值并且需要比较，如果 Column_A 和 Column_B 具有相同的值而不管大小写，那么 RESULT col 应该成功，如果它们有不同的值，RESULT col 应该像第 4 行和第 5 行一样有 FAIL

Column_A         Column_B          RESULT
------------------------------------------
 Apple           APPLE             SUCCESS
 Orange          ORANGE            SUCCESS
 Sun Flower      SUN FLOWER        SUCCESS
 Lily            LOTUS             FAIL
 Lotus           LILY              FAIL
 Olive           OLIVE             SUCCESS

我尝试了以下查询，

SELECT 
    Column_A, Column_B
    CASE
       IF Column_A == Column_B THEN SUCCEES
       ELSE FAIL 
    END AS RESULT 
FROM COMP_FRT;

Answer 1

SELECT column_A, column_B, CASE WHEN upper(Column_A) = upper(column_B) then 'SUCCESS' ELSE 'FAIL' END AS RESULT FROM COMP_FRT;

您可以根据自己的实际舒适度使用lower或upper或INITCAP

Answer 2

SELECT Column_A, Column_B,
CASE WHEN Lower(Column_A) = lower(Column_B) 
     THEN 'SUCCESS' ELSE 'FAIL' 
END AS RESULT 
FROM COMP_FRT;

Answer 3

如下图所示

SELECT Column_A, Column_B,
CASE when Column_A = Column_B THEN 'SUCCEES'
ELSE
'FAIL' 
END AS RESULT 
FROM COMP_FRT;