如何使用多个列值对子数组数据进行分组并单独对剩余的列值求和？

Question

如何按来源和日期分组，然后在下面的数组中 SUM 浏览量和收入

Array
(
    [0] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-31
            [Source] => Google
            [visits] => 6000
            [Pageviews] => 12,214
            [Revenue] => 25
        )
    [1] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-31
            [Source] => Google
            [visits] => 600
            [Pageviews] => 1015
            [Revenue] => 10
        )
    [2] => Array
          (
            [Source] => Analytics
            [Date] => 2017-10-31
            [Source] => Facebook
            [visits] => 600
            [Pageviews] => 1144
            [Revenue] => 40
        )

    [3] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-30
            [Source] => Google
            [visits] => 600
            [Pageviews] => 1144
            [Revenue] => 10
        )

    [4] => Array
         (
            [Source] => Analytics
            [Date] => 2017-10-30
            [Source] => Facebook
            [visits] => 1600
            [Pageviews] => 11,445
            [Revenue] => 5
        )
     [5] => Array
         (
            [Source] => Analytics
            [Date] => 2017-10-30
            [Source] => Facebook
            [visits] => 700
            [Pageviews] => 7,445
            [Revenue] => 8
        )
)

预期结果

Array
(
    [0] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-31
            [Source] => Google
            [visits] => 6600
            [Pageviews] => 13,229
            [Revenue] => 35
        )
    [1] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-31
            [Source] => Facebook
            [visits] => 600
            [Pageviews] => 1144
            [Revenue] => 40
        )
    [2] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-30
            [Source] => Google
            [visits] => 600
            [Pageviews] => 1144
            [Revenue] => 10
        )
    [3] => Array
        (
            [Source] => Analytics
            [Date] => 2017-10-30
            [Source] => Facebook
            [visits] => 2,300
            [Pageviews] => 18,890
            [Revenue] => 35
        )
) 

Answer 1

这是您需要的功能。干杯...

function combineAndSumUp ($myArray = []) {

    $finalArray = Array ();

    foreach ($myArray as $nkey => $nvalue) {

        $has = false;
        $fk = false;

        // Remove comma from numbers
        $nvalue['Pageviews'] = str_replace(",","",$nvalue["Pageviews"]);

        foreach ($finalArray as $fkey => $fvalue) {
            if ( ($fvalue['Date'] == $nvalue['Date']) && ($fvalue['Source'] == $nvalue['Source']) ) {
                $has = true;
                $fk = $fkey;
                break;
            }
        }

        if ( $has === false ) {
            $finalArray[] = $nvalue;
        } else {
            $finalArray[$fk]['visits'] += $nvalue['visits'];
            $finalArray[$fk]['Pageviews'] += $nvalue['Pageviews'];
            $finalArray[$fk]['Revenue'] += $nvalue['Revenue'];
        }

    }

    return $finalArray;
}

Answer 2

@J.D.Pace 的评论是什么意思：

您打算如何区分每个数组中的两个 Source 元素？

是……

“您的传入数据是不可能的，因为您可能在同一级别的数组中没有两个相同的键。您的数据在同一子数组中显示 "Source" => "Analytics" 和 "Source" => "Facebook"。” ...这意味着您的样本输入数据不准确。

因为我们不知道在您的情况下应该如何 并且因为Analytics 值对于这项任务完全没有价值，我将提供一个忽略这些不准确子数组元素的解决方案。

其他答案是工作太辛苦，写了太多代码。无需编写多个/嵌套循环，也无需对数据进行预排序。通过在输出数组中分配“复合临时键”并在处理时将输出数组用作“查找数组”，只需一个循环即可完成此任务。 isset() 是一种非常快速的方法，可以确定当前子数组是否包含新的数据组或之前是否遇到过该组。

完成后，您可以选择调用array_values() 来重新索引输出（如果需要）。您可能还想重新迭代以重新格式化页面浏览量以包含逗号 - 这再次由您自行决定。

代码：(Demo)

$array = [
    ['Date' => '2017-10-31', 'Source' => 'Google', 'visits' => '6000', 'Pageviews' => '12,214', 'Revenue' => '25'],
    ['Date' => '2017-10-31', 'Source' => 'Google', 'visits' => '600', 'Pageviews' => '1015', 'Revenue' => '10'],
    ['Date' => '2017-10-31', 'Source' => 'Facebook', 'visits' => '600', 'Pageviews' => '1144', 'Revenue' => '40'],
    ['Date' => '2017-10-30', 'Source' => 'Google', 'visits' => '600', 'Pageviews' => '1144', 'Revenue' => '10'],
    ['Date' => '2017-10-30', 'Source' => 'Facebook', 'visits' => '1600', 'Pageviews' => '11,445', 'Revenue' => '5'],
    ['Date' => '2017-10-30', 'Source' => 'Facebook', 'visits' => '700', 'Pageviews' => '7,445', 'Revenue' => '8'],
];

foreach ($array as $subarray) {
    $tempKey = $subarray['Source'].$subarray['Date'];  // this is the compound value
    $subarray['Pageviews'] = str_replace(',', '', $subarray['Pageviews']); // get rid of meddlesome comma
    if (isset($result[$tempKey])) {
        $result[$tempKey]['visits'] += $subarray['visits'];
        $result[$tempKey]['Pageviews'] += $subarray['Pageviews'];
        $result[$tempKey]['Revenue'] += $subarray['Revenue'];
    } else {
        $result[$tempKey] = $subarray;
    }
}
var_export(array_values($result));

输出：（删节）

array (
  0 => 
  array (
    'Date' => '2017-10-31',
    'Source' => 'Google',
    'visits' => 6600,
    'Pageviews' => 13229,
    'Revenue' => 35,
  ),
  ...
)

Answer 3

假设只有一个Source 索引。

试试这个：

array_multisort(array_column($arr, 'Date'), SORT_DESC,array_column($arr, 'Source'), SORT_DESC, $arr);

$new_arr = [];
$temp = ["Date"=>""];
$ctr = 0;
foreach($arr as $val) {
    if($val["Date"] == $temp["Date"] && $val["Source"] == $temp["Source"]) {
        $ctr2 = $ctr - 1;
        $new_arr[$ctr2]["visits"] += $val["visits"];
        $new_arr[$ctr2]["Pageviews"] += $val["Pageviews"];
        $new_arr[$ctr2]["Revenue"] += $val["Revenue"];
    } else {
        $new_arr[$ctr++] = $val;
    }
    $temp = $val;
}

print_r($new_arr);