MySQL SUM 与分组日期答案

【问题标题】：MySQL SUM With Grouped DateMySQL SUM 与分组日期
【发布时间】：2016-09-30 07:51:23
【问题描述】：

如何获取分组日期的数据价格？

SELECT store.date, store.pic, owner.name, 
SUM (CASE WHEN [>>GROUPED store.date<<] THEN store.price) AS total_price
FROM store
JOIN owner 
ON store.pic = owner.name GROUP BY store.date

我想这样显示：

+-------------+------+------------+
| date        | name |  price     | 
+-------------+------+------------+
| 2016-09-30  | John | 100000.00  |
| 2016-09-29  | Rey  | 125000.00  | 
+-------------+------+------------+

【问题讨论】：

显示表结构。否则你的查询是完美的......这里是一个例子：select category_id, sum(case when category_id=2 then product_min_price else 0 end) as ss, sum(case when category_id =1 then product_min_price else 0 end) as ttt from myzf.products

标签： php mysql sum case

【解决方案1】：

试试这个对你有帮助，

 SELECT store.date, store.pic, owner.name,SUM(store.price) AS total_price
 FROM store
 JOIN OWNER ON store.pic = owner.name
 GROUP BY store.date

我不明白你为什么在查询中使用 case 语句

【讨论】：