mysqli 案例问题 从内部案例中选择

Question

你好，这是我的代码，任何人都可以建议我哪里出错了，因为我遇到了错误

select m.verify 
CASE eore WHEN '1' THEN c.mobile from epmem m, empl c 
WHEN '2' THEN c.gender from epmem m, comp c 
ELSE NULL END, 
as 'expose' where (c.rid=m.mid) order by mid desc limit 50

错误是

 #1064 - Erreur de syntaxe près de 
'CASE eore WHEN '1' THEN c.mobile 
 from epmem m, empl c WHEN '2' THEN c.gender fro' Ã  la ligne 1 

这就是我想要达到的目标 我想将一张桌子与另一张桌子连接起来，另一张桌子是动态的，将根据案例价值....

我想要的是在案例 1 中将 empl 与 epmem 连接，在案例 2 时将 comp 与 epmem 连接，并在代码中选择相关数据......

Answer 1

每个CASE 语句都有END

SELECT m.verify,m.mid,
CASE eore
WHEN '1' THEN c.mobile
WHEN '2' THEN d.gender
ELSE NULL END AS 'expose'
FROM epmem m 
INNER JOIN empl c ON c.rid = m.mid
INNER JOIN comp d ON d.rid = m.mid
ORDER BY m.mid DESC
LIMIT 50

编辑：

SELECT m.mid,m.email,m.eore,m.date,m.ipj,m.verify,
    CASE eore WHEN '1' THEN d.mobile else c.gender END as expose1,
    CASE eore WHEN '1' THEN d.profile else c.profile END as expose2,
    CASE eore WHEN '1' THEN d.veri else c.mobile END as expose3
FROM epmem m
JOIN empl c ON c.rid = m.mid
JOIN comp d ON d.rid = m.mid
ORDER BY m.mid DESC
LIMIT 50