如何根据字段值提升结果答案

【问题标题】：How to boost results on the basis of fields values如何根据字段值提升结果
【发布时间】：2021-12-14 07:46:44
【问题描述】：

我一直坚持为这个问题创建查询。查询将关键字搜索以及产品评分。我有这些产品列表

[
  {
    name: 'pro',
    clickCount: 110,
    bookingCount: 57,
    isPromoted: 0,
  },
  {
    name: 'prod',
    clickCount: 13,
    bookingCount: 77,
    isPromoted: 0,
  },
  {
    name: 'produ',
    clickCount: 43,
    bookingCount: 10,
    isPromoted: 0,
  },
  {
    name: 'produc',
    clickCount: 5,
    bookingCount: 17,
    isPromoted: 0,
  },
  {
    name: 'product',
    clickCount: 89,
    bookingCount: 67,
    isPromoted: 0,
  },
  {
    name: 'products',
    clickCount: 1,
    bookingCount: 2,
    isPromoted: 1,
  },
  {
    name: 'products2',
    clickCount: 3,
    bookingCount: 4,
    isPromoted: 1,
  },
]

我需要将它们按以下顺序排序：

isPromoted=1 的产品将位于顶部（如果有多个具有相同值的产品，则具有 MAX(clickCount+bookingCount) 的产品将优先。
随后会出现具有 MAX(clickCount+bookingCount) 的产品。

关键字搜索pro的最终排序应该是这样的：

[
  {
    name: 'products2',
    clickCount: 3,
    bookingCount: 4,
    isPromoted: 1,
  },
  {
    name: 'products',
    clickCount: 1,
    bookingCount: 2,
    isPromoted: 1,
  },
  {
    name: 'pro',
    clickCount: 110,
    bookingCount: 57,
    isPromoted: 0,
  },
  {
    name: 'product',
    clickCount: 89,
    bookingCount: 67,
    isPromoted: 0,
  },
  {
    name: 'prod',
    clickCount: 13,
    bookingCount: 77,
    isPromoted: 0,
  },
  {
    name: 'produ',
    clickCount: 43,
    bookingCount: 10,
    isPromoted: 0,
  },
  {
    name: 'produc',
    clickCount: 5,
    bookingCount: 17,
    isPromoted: 0,
  },
]

我正在编写这个查询，但它没有给出想要的结果。

GET /products/_search
{
  
  "query": {
    "function_score": {
      "query": {
        "wildcard": {
          "name": "*pro*"
        }
      },
      
      "functions": [
         {
          "field_value_factor": {
            "field": "clickCount",
            "factor": 1.2,
            "modifier": "sqrt"
          }
         },
         {
          "field_value_factor": {
            "field": "clickCount",
            "factor": 1,
            "modifier": "sqrt"
          }
         },
         {
          "field_value_factor": {
            "field": "isPromoted",
            "factor": 1.5,
            "modifier": "sqrt"
          },
          "weight": 20
         }
        
      ],
      "boost_mode": "sum"
    }
  }
}

【问题讨论】：

标签： elasticsearch elastic-stack elasticsearch-5

【解决方案1】：

对于你想要的，我认为你可以在运行时计算一个 totalCount 字段，它返回计数的总和。然后您只需先使用isPromoted 字段进行排序，然后使用totalCount 字段：

映射：

{
    "mappings": {
        "properties": {
            "name": {
                "type": "text"
            },
            "clickCount": {
                "type": "integer"
            },
            "bookingCount": {
                "type": "integer"
            },
            "isPromoted": {
                "type": "integer"
            }
        }
    }
}

搜索查询：

{
  "runtime_mappings": {
    "totalCount": {
      "type": "long",
      "script": "emit(doc['clickCount'].value + doc['bookingCount'].value);"
    }
  },
  "query": {
        "match_all": {}
  },
    "sort": [
        {"isPromoted": "desc"},
        {"totalCount": "desc"}
    ]
}

【讨论】：