调用函数时，“If”语句被忽略[关闭]答案

【问题标题】："If" statement gets ignored when function is recalled [closed]调用函数时，“If”语句被忽略[关闭]
【发布时间】：2020-12-12 18:43:56
【问题描述】：

我正在尝试创建一个简单的程序，它会要求用户输入年龄，然后要求用户输入另一个年龄以找出差异。

当我要求用户确认他们的年龄时，我的程序中出现了问题。当我要求用户确认年龄时，如果用户回答确认他们的选择，我希望程序继续运行。但目前，我陷入了一个循环，即使用户输入确认，程序也会跳过我的if 语句并始终运行我的else: 语句。

#This program will prompt you to state your age and then will proceed to
#calculate how long till __ age

print("Hello. ")

while True:
    try:
        myAge = int(input("Please enter your age: ")) #int( makes func be a #
    except ValueError:
        print("I'm sorry, please enter your age as a numeric value.")
        continue #Continue function loops back to the function making it 'continue'
    else: #If it is a # then it breaks 
        break

#Going to ask for the second variable
print("You are " + str(myAge) + ".")
print("What is your desired age? ")
 
def secondV():
    desiredAge = int(input())
    print("You wish to be " + str(desiredAge) + "?")
    yourWish = input()
 
desiredAge = int(input())
print("Do you wish to be " + str(desiredAge) + "?")
yourWish = input()
 
def choose():
        if yourWish == "Yes" and yourWish == "yes" and yourWish == "y" and yourWish == "Y":
                    print("Okay... calculating")
                    print("To be " + str(desiredAge) + ", you would have to wait " + str(desiredAge - myAge) + " years. ")
                


else:
        print("Erm... please input your desired age now:")
        secondV()
        if desiredAge == 'yes' and desiredAge == 'Yes':
            print(Yes())
        else:
            No()

choose()
print('Goodbye.')

【问题讨论】：

你的意思是如果 yourWish == "Yes" or yourWish == "yes" or... yourWish 不可能是全部同时，只有一个或另一个。
and 意味着yourWish 应该是"Yes"、"yes"、"y"、"Y"，这是不可能的。您需要使用or 而不是and。这意味着如果任何条件为True 则执行循环
你可以用if yourWish.lower() in {'yes', 'y'}:更简洁地测试它
Thierry 与{'yes', 'y'} 一起使用的是set，以防您想知道。
对！那完全飞过我的头哈哈。非常感谢你们解决了我的问题。

标签： python python-3.x if-statement input

【解决方案1】：

有一些缩进错误，您使用 and 关键字而不是 or 关键字这是一个工作代码

print("Hello. ")

while True:
    try:
        myAge = int(input("Please enter your age: ")) #int( makes func be a #
    except ValueError:
        print("I'm sorry, please enter your age as a numeric value.")
        continue #Continue function loops back to the function making it 'continue'
    else: #If it is a # then it breaks 
        break


#Going to ask for the second variable


print("You are " + str(myAge) + ".")
 
 
print("What is your desired age? ")
 
def secondV():
    desiredAge = int(input())
    print("You wish to be " + str(desiredAge) + "?")
    yourWish = input()
 
desiredAge = int(input())
print("Do you wish to be " + str(desiredAge) + "?")
yourWish = input()
 
def choose():
    if yourWish == "Yes" or yourWish == "yes" or yourWish == "y" or yourWish == "Y":
        print("Okay... calculating")
        print("To be " + str(desiredAge) + ", you would have to wait " + str(desiredAge - myAge) + " years. ")
                


    else:
        print("Erm... please input your desired age now:")
        secondV()
        if yourWish == 'yes' or yourWish == 'Yes':
            print("Okay... calculating")
            print("To be " + str(desiredAge) + ", you would have to wait " + str(desiredAge - myAge) + " years. ")
        
        else:
            print("Erm... please input your desired age now:")
            secondV()
            choose()

choose()
 
print('Goodbye.')

【讨论】：