在循环中使用两个计数器

Question

我一直在家里使用 Python 制作基于文本的游戏，但在创建玩家和敌人之间的一小部分战斗时遇到了麻烦。战斗应该包括两个随机掷骰；一个给玩家，一个给外星人。如果外星人掷得比玩家高，则应将 +1 添加到 alien_wins 计数器，如果玩家获胜，则应将 +1 添加到 player_wins 计数器。

我想要发生的是当 player_wins 计数器达到 3 时，循环将停止并产生一条消息，当 alien_wins 达到 3 时也会发生同样的情况，但我无法完成这项工作。任何帮助将不胜感激，谢谢！

import random
from Tkinter import *

def Fight():

    player_wins = 0
    alien_wins = 0

    while player_wins <= 3:

        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1
            return

        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1
            return

        elif alien_roll == player_roll:
            contents.set("You both grapple eachother and eventually back off.")        
            return

            if player_wins == 3:
                contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
                win = True
                break
            elif alien_wins == 3:
                contents.set("You lose the fight to the alien. Game Over!")
                break

base = Tk()

contents = StringVar()
display = Message(base, textvariable = contents, relief=RAISED)
display.pack()

enterbutton = Button(base, text = 'Try Again', command = Fight).pack()

base.mainloop()

Answer 1

当任一条件（点 True 时，您想继续战斗（循环）。您需要在while 循环中添加另一个条件。

您只想在战斗结束后从函数返回，因此删除所有这些返回并在战斗结束后添加一个在循环之外的返回。此外，您只想在战斗结束后创建消息。

def Fight():

    player_wins = 0
    alien_wins = 0

    while player_wins <= 3 and alien_wins <= 3:

        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1

        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1

        elif alien_roll == player_roll:
            contents.set("You both grapple eachother and eventually back off.")        

    if player_wins == 3:
        contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
        win = True
    elif alien_wins == 3:
        contents.set("You lose the fight to the alien. Game Over!")
    return

Answer 2

我清理了一些东西。通过使循环依赖于player_wins 和alien_wins 是<= 3，您的循环的主要问题得到了解决。这样，只要其中一个命中3，循环就会终止，并且控制转到下面的if/else 语句，该语句将设置获胜者。

def Fight():    
    player_wins = 0
    alien_wins = 0

    while player_wins <= 3 and alien_wins <= 3:    
        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1
        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1
        else:
            contents.set("You both grapple eachother and eventually back off.")     

    if player_wins == 3:
        contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
        win = True
    else:
        contents.set("You lose the fight to the alien. Game Over!")

您也不需要那些break 语句，因为这完全脱离了循环。您可能正在考虑continue，它只会进入循环的下一次迭代，但即使这样也不需要，因为循环的全部内容只是一个if/else 语句，因此只会执行一个分支。

此外，您检查两个rolls 是否相等的elif 是不必要的，因为您已经排除了两者都不大于/小于另一个，因此可以假设它们相等。最后的if/else 也是如此，您可以在其中检查谁拥有3。如果我们不在循环中，我们知道有人有3，所以我们只需要实际检查单个玩家的得分。