【发布时间】:2019-06-01 11:03:47
【问题描述】:
我有 2 个实体:
- 背带
- 类别
我尝试根据“Recettes”表的每一行构建/列出一个表单并从控制器显示它。
有什么想法吗?
=========================
FORM_START
名称1(类型文本)|类别(ChoiceType)
名称2 (TypeText) |类别(ChoiceType)
名称3 (TypeText) |类别(ChoiceType)
[提交按钮]
FORM_END
=========================
实体接收
<?php
namespace App\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recettes
*
* @ORM\Table(name="recettes", indexes={@ORM\Index(name="categorie", columns={"categorie"})})
* @ORM\Entity
*/
class Recettes
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer", nullable=false)
* @ORM\Id
* @ORM\GeneratedValue(strategy="IDENTITY")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="nom", type="string", length=50, nullable=false)
*/
private $nom;
/**
* @var \Categories
*
* @ORM\ManyToOne(targetEntity="Categories")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="categorie", referencedColumnName="id")
* })
*/
private $categorie;
public function getId(): ?int
{
return $this->id;
}
public function getNom(): ?string
{
return $this->nom;
}
public function setNom(string $nom): self
{
$this->nom = $nom;
return $this;
}
public function getCategorie(): ?Categories
{
return $this->categorie;
}
public function setCategorie(?Categories $categorie): self
{
$this->categorie = $categorie;
return $this;
}
}
实体类别
<?php
namespace App\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Categories
*
* @ORM\Table(name="categories")
* @ORM\Entity
*/
class Categories
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer", nullable=false)
* @ORM\Id
* @ORM\GeneratedValue(strategy="IDENTITY")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="nom", type="string", length=50, nullable=false)
*/
private $nom;
public function getId(): ?int
{
return $this->id;
}
public function getNom(): ?string
{
return $this->nom;
}
public function setNom(string $nom): self
{
$this->nom = $nom;
return $this;
}
}
【问题讨论】:
标签: arrays forms loops symfony entity