【发布时间】:2013-09-17 20:54:58
【问题描述】:
您好,这个查询需要 100 毫秒,我认为它太多了?
SELECT
COUNT(
s0_.id
) AS sclr0,
s0_.id AS id1,
s0_.status AS status2,
...
s0_.public AS public22,
t1_.username AS username23,
t1_.username_canonical AS username_canonical24,
...
t1_.old_new AS old_new57,
t1_.image_name AS image_name58,
s0_.user_id AS user_id59
FROM
statuses s0_
INNER JOIN
users t1_ ON s0_.user_id = t1_.id
WHERE
s0_.time >= ? AND s0_.suggested_status = 1
GROUP BY
t1_.id
ORDER BY
sclr0 DESC
LIMIT
10
Parameters: [1376784000]
[Display runnable query]
Time: 108.53 ms [ - Explain query ]
以及解释:
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1_ index PRIMARY PRIMARY 4 12132 Using temporary; Using filesort
1 SIMPLE s0_ ref IDX_4BF01E11A76ED395 IDX_4BF01E11A76ED395 4 db.t1_.id 3 Using where
我做错了吗?
查询点是选择所有发布状态标记为“建议”的用户,并按每个用户上个月的建议状态数对用户进行排序。
【问题讨论】:
-
您可能会考虑创建一个命令来缓存此查询的结果并使用 cronjob 定期执行该命令。然后访问应用程序中的缓存值。
标签: php symfony doctrine-orm doctrine