在 Symfony 3.3 中将数据传递给 buildForm()

Question

我正在尝试将当前经过身份验证的用户传递给 buildForm 几个小时，我搜索了谷歌...没有任何效果 我得到的错误是

表单的视图数据应该是 AppBundle\Entity\AdsList 类的一个实例，但它是一个 (n) 数组。您可以通过将“data_class”选项设置为 null 或添加将 a(n) 数组转换为 AppBundle\Entity\AdsList 实例的视图转换器来避免此错误。

在->getForm();

我必须想好要做什么......视图转换器......（https://symfony.com/doc/current/form/data_transformers.html）

但我只有一个整数...

如果你有一个很好的例子，我还想从内容中生成独特的 slug（最终版本不会有标题字段）:)

提前感谢:)

AgencyController.php

/**
 * @Route("/agency/post", name="agency_post")
 */
public function agencyNewAd(Request $request)
{
   //  $agency = $this->get('security.token_storage')->getToken()->getUser(); ( this didn't worked .. )
    $form = $this->createForm(AgencyNewAdType::class, array(
        'postedBy' => $this->getUser(),
    ));
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {

        $ad = $form->getData();

        // save the task to the database
        $em = $this->getDoctrine()->getManager();
        $em->persist($ad);
        $em->flush();
        // return new Response('Saved new Post with id ' . $ad->getId());
        return $this->redirectToRoute('agency_admin');
    }
    return $this->render('agency/new_ad.html.twig', [
        'adForm' => $form->createView()
    ]);
}

AgencyNewAdType.php

class AgencyNewAdType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
    // https://stackoverflow.com/questions/36905490/how-to-pass-parameter-to-formtype-constructor-from-controller
    $builder
        ->add('title', TextType::class)
        ->add('content', TextareaType::class)
        ->add('category', EntityType::class, array(
            // query choices from Category.Name
            'class' => 'AppBundle:CategoryAd',
            'choice_label' => 'name',
        ))
        ->add('postedAt', DateType::class)
        ->add('postedBy',HiddenType::class, array(
            'data' => $options['postedBy']
        ))
        ->add('save', SubmitType::class, array('label' => 'Create Post'))
        ->getForm();

}
public function configureOptions(OptionsResolver $resolver)
   {
    $resolver->setDefaults(array(
        'postedBy' => null,
        'data_class' => 'AppBundle\Entity\AdsList',
    ));
   }
}

Answer 1

我需要将参数传递给表单，使其看起来像

public function agencyNewAd(Request $request): Response
{
    $pass = new AdsList();
    $pass->setPostedBy($this->getUser());
    $form = $this->createForm(AgencyNewAdType::class, $pass);
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        // $form->getData() holds the submitted values iN MeM
        $ad = $form->getData();

        // save the ad to the database
        $em = $this->getDoctrine()->getManager();
        $em->persist($ad);
        $em->flush();
        // return new Response('Saved new Post with id ' . $ad->getId());
        return $this->redirectToRoute('agency_admin');
    }
    return $this->render('agency/new_ad.html.twig', [
        'adForm' => $form->createView()
    ]);
}

并且在表单中我需要删除postedBy ...

public function buildForm(FormBuilderInterface $builder, array $options)
{
    // https://stackoverflow.com/questions/36905490/how-to-pass-parameter-to-formtype-constructor-from-controller
    $builder
        ->add('title', TextType::class)
        ->add('content', TextareaType::class)
        ->add('category', EntityType::class, array(
            // query choices from Category.Name
            'class' => 'AppBundle:CategoryAd',
            'choice_label' => 'name',
        ))
        ->add('postedAt', DateType::class)
        ->add('save', SubmitType::class, array('label' => 'Create Post'))
        ->getForm();

}

Answer 2

在控制器中创建时你错过了一个参数，第二个参数应该是你连接到表单的对象，第三个是选项数组，所以它看起来像：

public function agencyNewAd(Request $request)
{
    $ad = new AdsList();
    $form = $this->createForm(AgencyNewAdType::class, $ad, array(
        'postedBy' => $this->getUser(),
    ));
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $em = $this->getDoctrine()->getManager();
        $em->persist($ad);
        $em->flush();

        return $this->redirectToRoute('agency_admin');
    }
    return $this->render('agency/new_ad.html.twig', [
        'adForm' => $form->createView()
    ]);
}

另一种方法是将您的选项传递给表单的构造，如下所示：

public function agencyNewAd(Request $request)
{
    $ad = new AdsList();
    $form = $this->createForm(new AgencyNewAdType($this->getUser()), $ad);

然后在 AgencyNewAdType 的构造函数中，您将接受您的参数，在本例中为当前登录用户。