【发布时间】:2016-10-20 16:01:50
【问题描述】:
我收集了 Country 字段:name、aaa、bbb、ccc、ddd。
例子:
{_id: xxx1, name: "USA", aaa: "daf", ccc: "sdfgsdf", ddd: "234"}
{_id: xxx2, name: "Mexico", aaa: "dfg", bbb: "fdsgsdf"}
{_id: xxx3, name: "Germany", bbb: "ddfgaf"}
{_id: xxx4, name: "France"}
在我的 Symfony 应用程序的控制器中,我将所有对象获取到变量 $countries 和下一个:
foreach ($countries as $country) {
//how can I get here fields for current object?
//For _id: xxx1 I would like receive "_id, name, aaa, ccc, ddd" and for _id: xxx4 I would like receive "_id, name"
}
【问题讨论】:
-
您有什么想问的吗?
-
它似乎作为注释嵌入在代码中。
标签: php mongodb symfony doctrine