Doctrine n:m 关系未定义索引：BasicEntityPersister.php 中的 joinColumns

Question

我的问题与Undefined index: inverseJoinColumns while trying to define ManyToMany relationship between two entities这个问题密切相关

我正在尝试查找所有没有章节的书籍。 ->findBy(array("section"=>null)

这是我的实体配置： 编辑书籍

    /**
 * @var \Doctrine\Common\Collections\Collection
 *
 * @ORM\ManyToMany(targetEntity="Sections", inversedBy="editedBook")
 * @ORM\JoinTable(name="edited_book_has_section",
 *   joinColumns={
 *     @ORM\JoinColumn(name="edited_book_id", referencedColumnName="id")
 *   },
 *   inverseJoinColumns={
 *     @ORM\JoinColumn(name="section_id", referencedColumnName="id")
 *   }
 * )
 */ 
private $section;

这是我的实体配置： 部分

/**
 * Bidirectional (INVERSE SIDE)
 *
 * @ORM\ManyToMany(targetEntity="EditedBooks", mappedBy="section")
 */       
private $editedBook;

我遇到的错误

未定义索引：BasicEntityPersister.php 中的 joinColumns

我也试过了

    /**
 * @var \Doctrine\Common\Collections\Collection
 *
 * @ORM\ManyToMany(targetEntity="Sections", inversedBy="editedBook")
 * @ORM\JoinTable(name="edited_book_has_section")
 */ 

或切换定义但我收到此错误

You cannot search for the association field '\Entity\EditedBooks#section', because it is the inverse side of an association. Find methods only work on owning side associations.

解决方法： 今天我试图解决我的editedBooksRepository中的querybuilder的问题

        $query = $qb->select('books')
        ->from('Bundle:EditedBooks', 'books')
        ->leftJoin('books.section', 'sec')
        ->addSelect('COUNT(sec.id) AS sec_count')
        ->andWhere('sec_count = 0');

但我收到以下错误：

执行 'SELECT e0_.id AS id0, e0_.doi 时发生异常 AS doi1, e0_.isbn_print AS isbn_print2, e0_.isbn_electronic AS isbn_electronic3, e0_.publication_date AS publication_date4, e0_.price_print AS price_print5, e0_.price_electronic AS price_electronic6, e0_.summary AS summary7, e0_.title AS title8, e0_.ongoing AS 正在进行9, e0_.pages AS pages10, e0_.illustrations AS 插图11，e0_.entry_date AS entry_date12，e0_.google_id AS google_id13, e0_.specialIssue_comment AS specialIssue_comment14, e0_.deleted AS 已删除15, e0_.specialIssue_id AS specialIssue_id16, COUNT(s1_.id) AS sclr17，e0_.book_series_id AS book_series_id18， e0_.copyright_id AS copyright_id19, e0_.publisher_id AS publisher_id20 从edited_books e0_ 左加入edited_book_has_section e2_ ON e0_.id = e2_.editedbooks_id 左连接部分 s1_ ON s1_.id = e2_.sections_id WHERE sclr17 = 0'：

SQLSTATE[42S22]：找不到列：1054 未知列 'sclr17' 在 'where子句'

但对我来说，sclr17 似乎存在，我错过了什么吗？

丑陋的解决方法 我知道这样做是不对的，但有时男人不得不做男人必须做的事：

    $noSection = new Sections();      
    $noSection->setTitle("Sectionless");
    //add all the books 
    $noSection->setEditedBook(new ArrayCollection($books));
    //remove the assigned ones
    foreach($sections as $section){
        $sBooks = $section->getEditedBook();
        foreach($sBooks as $b){
            $noSection->removeEditedBook($b);
        }
    }

有了肮脏的修复，它现在可以工作了，但我很高兴有任何其他解决方案。

Answer 1

这是一个工作示例

    class Audio
    {
      /**
      * @ORM\ManyToMany(targetEntity="Acme\MyBundle\Entity\Groupe",inversedBy="audios")
      */
      private $groupes;

  class Groupe
  {

    /**
    * @ORM\ManyToMany(targetEntity="Acme\MyBundle\Entity\Audio",mappedBy="groupes")
    */
    private $audios;

请注意 mappedby 和 inversedby 以及属性的末尾有一个“s”。 （Groupe => 私人 $groupe s ）。也许对你有帮助

Answer 2

你不能只检查 null 吗？

$query = $qb->select('books')
    ->from('Bundle:EditedBooks', 'books')
    ->leftJoin('books.section', 'sec')
    ->where('sec IS NULL');