Google Maps Fusion Layer 忽略 WHERE 子句

Question

我在使融合表层中的 where 子句实际执行任何操作时遇到问题。

下面应该做的是从我的融合表中选择“收入”大于 100 的所有行（或者如果您在 where 子句中交换代码，则选择特定几何 (MSOA)）。

融合表列average_income为Number类型，MSOA11CD为Text类型。

这里有一个关于同一主题的老问题，但通过我没有的语法错误解决了。 "WHERE" clauses being ignored in Fusion Table Layer in Google Maps

在这里提琴： http://jsfiddle.net/dqthnw7s/

layer = new google.maps.FusionTablesLayer({
    map: map,
    heatmap: {
        enabled: false
    },
    query: {
        select: "*",
        from: "1QEMdQUSmsdEZs9vAchHeKPG_CsKa7L0zW0SBJSCu",
        where: "average_income > 100",
        //tried this too
        //where: 'MSOA11CD = \'E02004590\''

    },
    styles: [{
       where: "average_income > 1000",
        polygonOptions: {
            fillColor: '#002951'
        }
    }, {
        where: "average_income > 800 AND average_income <= 1000",
        polygonOptions: {
            fillColor: '#003466'
        }
    }, {
        where: 'average_income > 100 AND average_income <= 800',
        polygonOptions: {
            fillColor: '#376798'
        }
    }]
});

融合表： https://www.google.com/fusiontables/DataSource?docid=1QEMdQUSmsdEZs9vAchHeKPG_CsKa7L0zW0SBJSCu#rows:id=1

任何帮助将不胜感激！

Answer 1

选择“*”无效。那需要是一个“几何”列。

layer = new google.maps.FusionTablesLayer({
    map: map,
    heatmap: {
        enabled: false
    },
    query: {
        select: "geometry",
        from: "1QEMdQUSmsdEZs9vAchHeKPG_CsKa7L0zW0SBJSCu",
        where: "average_income > 100",
        //tried this too
        //where: 'MSOA_CODE = \'E02004590\''

    },
    styles: [{
       where: "average_income > 1000",
        polygonOptions: {
            fillColor: '#002951'
        }
    }, {
        where: "average_income > 800 AND average_income <= 1000",
        polygonOptions: {
            fillColor: '#003466'
        }
    }, {
        where: 'average_income > 100 AND average_income <= 800',
        polygonOptions: {
            fillColor: '#376798'
        }
    }]
});

updated fiddle