显示标签但不显示数据

Question

我正在开发代码以从远程 Ajax 获取数据，但无法显示所需的数据。

但是标签的名称显示正确。

从远程，在 PHP 中我有这个：

for ( $i = $start; $i <= $end; $i = $i + 86400 ) {
    $SQDate     = date( 'Y-m-d', $i ); 
    $PMS_ci     = $this->getPMS_ci_status($SQDate);
    $PMS_co     = $this->getPMS_co_status($SQDate);
    if($PMS_ci["sum"] == "")
        $PMS_ci["sum"] = "0";
    if($PMS_co["sum"] == "")
        $PMS_co["sum"] = "0";
    $arrival[]  = $PMS_ci["sum"];
    $departure[]= $PMS_co["sum"];
}
$data[]     = array("name" => "Arrival", "data" => join($arrival,","));
$data[]     = array("name" => "Departure", "data" => join($departure,","));

return JSON_encode($data);

端 Javascript：

retour = JSON.parse(data.message);
Highcharts.chart('container', {
    chart: {
        type: 'spline'
        },
    .../...
    ,
    series: [{name: retour[0].name ,data: retour[0].data},
             {name: retour[1].name, data: retour[1].data}],
    navigation: {
    .../...

数据内容返回：

[
    {
        "name":"Arrival",
        "data":"[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,3,0,0,0,0,0,0,0,0,0,0,0]"
    },
    {
        "name":"Departure",
        "data":"[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,3,0,0,0,0,0,0,0,0,0,0]"
    }
]

在所有情况下，都不会显示所需的数据，但会正确显示名称。

我不知道为什么。我在这里阅读了一些主题但没有成功。应该怎么做才能确保数据与标签一起显示？

Answer 1

来自

$data[]     = array("name" => "Arrival", "data" => join($arrival,","));
                                                   ^
                                            No need of join, json_encode
                                            takes care of it

收件人

$data[]     = array("name" => "Arrival", "data" => $arrival);

你的 json 变成了

来自

[{"name":"Arrival","data":"[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,3,0,0,0,0,0,0,0,0,0,0,0]"},{"name":"Departure","data":"[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,3,0,0,0,0,0,0,0,0,0,0]"}]
                          ^
                         Should be array not string

收件人

[{"name":"Arrival","data":[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,3,0,0,0,0,0,0,0,0,0,0,0]},{"name":"Departure","data":[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,3,0,0,0,0,0,0,0,0,0,0]}]

你可以像下面这样重写你的代码

for ( $i = $start; $i <= $end; $i = $i + 86400 ) 
    {
          $SQDate     = date( 'Y-m-d', $i ); 
          $PMS_ci     = $this->getPMS_ci_status($SQDate);
          $PMS_co     = $this->getPMS_co_status($SQDate);

          $arrival[]  =  $PMS_ci["sum"]+0;
          $departure[]= $PMS_co["sum"]+0;
    }

        $data[]     = array("name" => "Arrival", "data" =>$arrival);
        $data[]     = array("name" => "Departure", "data" => $departure);

        // Return to caller (since PHP 5.3.3)
        // and from caller do echo  
        return json_encode($data,JSON_NUMERIC_CHECK);