【发布时间】:2017-12-25 21:38:50
【问题描述】:
我需要一个组织结构图树,并且我希望能够在任何级别折叠和展开节点。我是 JGraphX 的新手,但从我读到的内容看来,实现折叠的方法是对顶点进行分组。问题是当我创建组时,它会将所有子顶点放在父顶点内。
下面是一些示例代码,提供了很好的布局但不支持折叠:
package com.mxgraph.examples.swing;
import java.util.ArrayList;
import java.util.List;
import javax.swing.JFrame;
import javax.swing.SwingConstants;
import com.mxgraph.layout.mxCompactTreeLayout;
import com.mxgraph.layout.hierarchical.mxHierarchicalLayout;
import com.mxgraph.model.mxGeometry;
import com.mxgraph.swing.mxGraphComponent;
import com.mxgraph.util.mxConstants;
import com.mxgraph.util.mxPoint;
import com.mxgraph.util.mxRectangle;
import com.mxgraph.view.mxGraph;
import com.mxgraph.layout.hierarchical.mxHierarchicalLayout;
public class HelloWorld extends JFrame
{
/**
*
*/
private static final long serialVersionUID = -2707712944901661771L;
public HelloWorld()
{
super("Hello, puppies!");
mxGraph graph = new mxGraph();
Object parent = graph.getDefaultParent();
graph.getModel().beginUpdate();
try
{
//Notice that the parent is the default parent...
//The hierarchical structure looks great but I cannot collapse/expand the tree.
Object vDogsRoot = graph.insertVertex(parent, null, "DOG", 0, 0, 80, 30);
Object v2 = graph.insertVertex(parent, null, "Shar Pei", 0, 0, 80, 30);
Object v3 = graph.insertVertex(parent, null, "Pug", 0, 0, 80, 30);
Object v4 = graph.insertVertex(parent, null, "Cocker Spaniel", 0, 0, 80, 30);
Object v5 = graph.insertVertex(parent, null, "Pit Bull", 0, 0, 80, 30);
Object v6 = graph.insertVertex(parent, null, "Chihuahua", 0, 0, 80, 30);
graph.insertEdge(parent, null, "", vDogsRoot, v2);
graph.insertEdge(parent, null, "", vDogsRoot, v3);
graph.insertEdge(parent, null, "", vDogsRoot, v4);
graph.insertEdge(parent, null, "", vDogsRoot, v5);
graph.insertEdge(parent, null, "", vDogsRoot, v6);
mxHierarchicalLayout layout = new mxHierarchicalLayout(graph);
layout.setUseBoundingBox(false);
layout.execute(parent);
}
finally
{
graph.getModel().endUpdate();
}
mxGraphComponent graphComponent = new mxGraphComponent(graph);
getContentPane().add(graphComponent);
}
public static void main(String[] args)
{
HelloWorld frame = new HelloWorld();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setSize(400, 320);
frame.setVisible(true);
}
}
生产:
很好的开始,但没有折叠按钮。以下代码演示了我遇到的问题。为了支持折叠,我尝试通过将顶点的父级从默认父级更改为树的根 vDogVertex 来创建一个组。这变得可折叠,但是所有子顶点都在 vDogVertex 内部,这会破坏树的布局。
package com.mxgraph.examples.swing;
import java.util.ArrayList;
import java.util.List;
import javax.swing.JFrame;
import javax.swing.SwingConstants;
import com.mxgraph.layout.mxCompactTreeLayout;
import com.mxgraph.layout.hierarchical.mxHierarchicalLayout;
import com.mxgraph.model.mxGeometry;
import com.mxgraph.swing.mxGraphComponent;
import com.mxgraph.util.mxConstants;
import com.mxgraph.util.mxPoint;
import com.mxgraph.util.mxRectangle;
import com.mxgraph.view.mxGraph;
import com.mxgraph.layout.hierarchical.mxHierarchicalLayout;
public class HelloWorld extends JFrame
{
/**
*
*/
private static final long serialVersionUID = -2707712944901661771L;
public HelloWorld()
{
super("Hello, puppies!");
mxGraph graph = new mxGraph();
Object parent = graph.getDefaultParent();
graph.getModel().beginUpdate();
try
{
//Notice this time the parent is the vDogsRoot vertex.
//This creates a cell group if I understand correctly.
Object vDogsRoot = graph.insertVertex(parent, null, "DOG", 0, 0, 80, 30, "");
Object v2 = graph.insertVertex(vDogsRoot, null, "Shar Pei", 0, 0, 80, 30, "");
Object v3 = graph.insertVertex(vDogsRoot, null, "Pug", 0, 0, 80, 30, "");
Object v4 = graph.insertVertex(vDogsRoot, null, "Cocker Spaniel", 0, 0, 80, 30, "");
Object v5 = graph.insertVertex(vDogsRoot, null, "Pit Bull", 0, 0, 80, 30, "");
Object v6 = graph.insertVertex(vDogsRoot, null, "Chihuahua", 0, 0, 80, 30, "");
graph.insertEdge(parent, null, "", vDogsRoot, v2);
graph.insertEdge(parent, null, "", vDogsRoot, v3);
graph.insertEdge(parent, null, "", vDogsRoot, v4);
graph.insertEdge(parent, null, "", vDogsRoot, v5);
graph.insertEdge(parent, null, "", vDogsRoot, v6);
mxHierarchicalLayout layout = new mxHierarchicalLayout(graph);
layout.setUseBoundingBox(false);
layout.execute(vDogsRoot); //apply the layout to the root group node.
layout.execute(parent);
}
finally
{
graph.getModel().endUpdate();
}
mxGraphComponent graphComponent = new mxGraphComponent(graph);
getContentPane().add(graphComponent);
}
public static void main(String[] args)
{
HelloWorld frame = new HelloWorld();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setSize(400, 320);
frame.setVisible(true);
}
}
产生: (注意折叠按钮)
如何防止顶点位于单元组的父单元内?我希望树层次结构得到维护但可折叠。我是否在使用 Cell Groups 的正确路径上?我做错了什么?
我怀疑我只需要告诉单元组的父级 (vDogsRoot) 允许将单元格绘制到其边界之外,但我还没有看到这样做的方法。或者,也许我采取了完全错误的方法。认为这应该是一件微不足道的事情,但我尝试了许多不同的事情,并在谷歌上搜索/阅读了许多文档,但还没有成功。
更新 1:
组不是我在这里需要的。我只需要遍历有向树并切换显示所选节点下方的节点。在 mxGraph 示例文件夹中找到一个名为 tree.html 的 java 脚本示例。只需将该示例从 JavaScript 转换为 Java。
【问题讨论】: