【发布时间】:2020-01-17 16:35:26
【问题描述】:
我有一个长期的时间序列(22 年),并希望按月对数据进行分组并平均每小时来获得昼夜温度曲线。下面是我的数据集。
Datetime.LST ruc.197.118 narr.225.118 KLAF VAIv212_08748740771
1 12/31/1996 18:00 NA -0.7843 NA NA
2 12/31/1996 19:00 NA -1.2432 NA NA
3 12/31/1996 20:00 NA -1.7022 NA NA
4 12/31/1996 21:00 NA -2.1611 NA NA
5 12/31/1996 22:00 NA -2.1026 NA NA
6 12/31/1996 23:00 NA -2.0440 NA NA
7 1/1/1997 0:00 NA -1.9854 NA 0.4120480
8 1/1/1997 1:00 NA -1.7506 NA 0.4400940
9 1/1/1997 2:00 NA -1.5157 NA 0.4594420
10 1/1/1997 3:00 NA -1.2808 NA 0.3232730
11 1/1/1997 4:00 NA -0.9326 NA 0.0754700
12 1/1/1997 5:00 NA -0.5844 NA -0.0730896
13 1/1/1997 6:00 NA -0.2363 NA -0.1574400
14 1/1/1997 7:00 NA 0.3422 NA -0.2461240
15 1/1/1997 8:00 NA 0.9207 NA -0.0277405
temperature_data <- read.csv(temp_hourly, stringsAsFactors = FALSE)
monthly_hourly <- temperature_data %>%
dmy_hm(.$Datetime.LST, tz = "GMT") %>%
dplyr::group_by(month=format(Datetime.LST,'%m'), hour=format(as.POSIXct(cut(Datetime.LST, breaks = 'hour')),"%H")) %>%
summarise(meanVal=mean(val,na.rm=TRUE))
}
使用dput的示例数据集
> dput(head(temperature_data[, c(1,2,3,4,5)]))
structure(list(Datetime.LST = c("12/31/1996 18:00", "12/31/1996 19:00",
"12/31/1996 20:00", "12/31/1996 21:00", "12/31/1996 22:00", "12/31/1996 23:00"
), ruc.197.118 = c(NA_real_, NA_real_, NA_real_, NA_real_, NA_real_,
NA_real_), narr.225.118 = c(-0.7843, -1.2432, -1.7022, -2.1611,
-2.1026, -2.044), KLAF = c(NA_integer_, NA_integer_, NA_integer_,
NA_integer_, NA_integer_, NA_integer_), VAIv212_08748740771 = c(NA_real_,
NA_real_, NA_real_, NA_real_, NA_real_, NA_real_)), .Names = c("Datetime.LST",
"ruc.197.118", "narr.225.118", "KLAF", "VAIv212_08748740771"), row.names = c(NA,
6L), class = "data.frame")
Datetime.LST 作为ch 数据类型引入。我在获取不同的日期包(lubridate)以同意dplyr 的group_by 函数时遇到了一些问题。
使用下面的 Andrews cmets,更新代码和当前输出:
temperature_data <- read.csv(temp_hourly, stringsAsFactors = FALSE)
monthly_hourly <- temperature_data %>%
mutate(Datetime.LST = mdy_hm(Datetime.LST, tz = "GMT"),
day = day(Datetime.LST),
month = month(Datetime.LST),
hour = hour(Datetime.LST)) %>%
group_by(month, hour) %>%
summarise(
ruc.197.118 = mean(ruc.197.118, na.rm = TRUE),
narr.225.118 = mean(narr.225.118, na.rm = TRUE),
KLAF = mean(KLAF, na.rm = TRUE),
VAIv212_08748740771 = mean(VAIv212_08748740771, na.rm = TRUE)
) %>%
# next step creates a dummy year to group month/day/hr as datetime
mutate(month_name = month(month, label = TRUE))
ggplot(data = monthly_hourly,aes(x = hour)) +
geom_line(color = "red", aes(y = ruc.197.118)) +
geom_line(color = "blue", aes(y = narr.225.118)) +
geom_line(color = "black", aes(y = KLAF)) +
geom_line(color = "orange", aes(y = VAIv212_08748740771)) +
xlab("Temperature degC") +
ylab("Hour of Day") +
facet_wrap(~ month_name)
【问题讨论】:
-
嘿,有一些额外的东西来看看已经做了什么以及可以做什么会很有帮助。您能否发布一些您尝试过的代码(使用
group_by)和您的数据样本(使用dput),以确保发布的解决方案专门适用于您的数据? -
(作为初始尝试,
lubridate的month()函数将从日期/时间变量中提取月份,然后您可以将其用作新变量以分组(@ 987654338@...),如果您的Datetime.LST已经格式化? -
@AndrewBaxter 推进了一些编辑。
-
嗨@twseewx,您还有其他问题需要解决吗?如果事情不起作用,请详细说明,或者如果一切都解决了,请将问题标记为已回答。
标签: r dataframe date ggplot2 dplyr