【发布时间】:2019-06-07 19:10:42
【问题描述】:
我有一个类似于以下的数据框,我们称之为“df”:
id value time
a 1 1
a 1.5 2
a 2 3
a 2.5 4
b 1 1
b 1.5 2
b 2 3
b 2.5 4
我正在这个数据帧上通过 Python 中的“id”运行各种回归。通常,这需要按“id”进行分组,然后将函数应用于计算回归的分组。
我正在 Scipy 的统计库中使用 2 种类似的回归技术:
-
Theil-Sen 估计器:
(https://docs.scipy.org/doc/scipy-0.15.1/reference/generated/scipy.stats.mstats.theilslopes.html)
-
Siegel 估计器:
(https://docs.scipy.org/doc/scipy/reference/generated/scipy.stats.siegelslopes.html)。
这两者都采用相同类型的数据。因此,除了实际使用的技术之外,计算它们的函数应该是相同的。
对于 Theil-Sen,我编写了以下函数以及将应用于该函数的 groupby 语句:
def theil_reg(df, xcol, ycol):
model = stats.theilslopes(ycol,xcol)
return pd.Series(model)
out = df.groupby('id').apply(theil_reg, xcol='time', ycol='value')
但是,我收到以下错误,我一直很难理解如何解决:
ValueError: 无法将字符串转换为浮点数:'time'
实际变量 time 是一个 numpy 浮点对象,所以它不是字符串。这让我相信stats.theilslopes 函数没有识别出 time 是数据框中的一列,而是使用“时间”作为函数的字符串输入。
但是,如果是这种情况,那么这似乎是 stats.theilslopes 包中的一个错误,需要 Scipy 解决。我认为是这种情况的原因是因为与上面完全相同的功能,但使用siegelslopes 包,工作得非常好,并提供了我期望的输出,并且它们基本上是相同的估计输入。
在 Siegel 上执行以下操作:
def siegel_reg(df, xcol, ycol):
model = stats.siegelslopes(ycol,xcol)
return pd.Series(model)
out = df.groupby('id').apply(siegel_reg, xcol='time',ycol='value')
不会对 time 变量产生任何错误,并根据需要进行回归。
有人对我是否在这里遗漏了什么有想法吗?如果是这样,我会很感激任何想法,或者如果不是,任何关于如何用 Scipy 解决这个问题的想法。
编辑:这是我运行此脚本时显示的完整错误消息:
ValueError Traceback (most recent call last)
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in apply(self, func, *args, **kwargs)
688 try:
--> 689 result = self._python_apply_general(f)
690 except Exception:
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in _python_apply_general(self, f)
706 keys, values, mutated = self.grouper.apply(f, self._selected_obj,
--> 707 self.axis)
708
C:\Anaconda\lib\site-packages\pandas\core\groupby\ops.py in apply(self, f, data, axis)
189 group_axes = _get_axes(group)
--> 190 res = f(group)
191 if not _is_indexed_like(res, group_axes):
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in f(g)
678 with np.errstate(all='ignore'):
--> 679 return func(g, *args, **kwargs)
680 else:
<ipython-input-506-0a1696f0aecd> in theil_reg(df, xcol, ycol)
1 def theil_reg(df, xcol, ycol):
----> 2 model = stats.theilslopes(ycol,xcol)
3 return pd.Series(model)
C:\Anaconda\lib\site-packages\scipy\stats\_stats_mstats_common.py in
theilslopes(y, x, alpha)
221 else:
--> 222 x = np.array(x, dtype=float).flatten()
223 if len(x) != len(y):
ValueError: could not convert string to float: 'time'
During handling of the above exception, another exception occurred:
ValueError Traceback (most recent call last)
<ipython-input-507-9a199e0ce924> in <module>
----> 1 df_accel_correct.groupby('chart').apply(theil_reg, xcol='time',
ycol='value')
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in apply(self, func, *args, **kwargs)
699
700 with _group_selection_context(self):
--> 701 return self._python_apply_general(f)
702
703 return result
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in _python_apply_general(self, f)
705 def _python_apply_general(self, f):
706 keys, values, mutated = self.grouper.apply(f,
self._selected_obj,
--> 707 self.axis)
708
709 return self._wrap_applied_output(
C:\Anaconda\lib\site-packages\pandas\core\groupby\ops.py in apply(self, f, data, axis)
188 # group might be modified
189 group_axes = _get_axes(group)
--> 190 res = f(group)
191 if not _is_indexed_like(res, group_axes):
192 mutated = True
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in f(g)
677 def f(g):
678 with np.errstate(all='ignore'):
--> 679 return func(g, *args, **kwargs)
680 else:
681 raise ValueError('func must be a callable if args or '
<ipython-input-506-0a1696f0aecd> in theil_reg(df, xcol, ycol)
1 def theil_reg(df, xcol, ycol):
----> 2 model = stats.theilslopes(ycol,xcol)
3 return pd.Series(model)
C:\Anaconda\lib\site-packages\scipy\stats\_stats_mstats_common.py in theilslopes(y, x, alpha)
220 x = np.arange(len(y), dtype=float)
221 else:
--> 222 x = np.array(x, dtype=float).flatten()
223 if len(x) != len(y):
224 raise ValueError("Incompatible lengths ! (%s<>%s)" % (len(y), len(x)))
ValueError: could not convert string to float: 'time'
更新2:在函数中调用df后,收到如下错误信息:
ValueError Traceback (most recent call last)
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in apply(self, func, *args, **kwargs)
688 try:
--> 689 result = self._python_apply_general(f)
690 except Exception:
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in _python_apply_general(self, f)
706 keys, values, mutated = self.grouper.apply(f, self._selected_obj,
--> 707 self.axis)
708
C:\Anaconda\lib\site-packages\pandas\core\groupby\ops.py in apply(self, f, data, axis)
189 group_axes = _get_axes(group)
--> 190 res = f(group)
191 if not _is_indexed_like(res, group_axes):
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in f(g)
678 with np.errstate(all='ignore'):
--> 679 return func(g, *args, **kwargs)
680 else:
<ipython-input-563-5db69048f347> in theil_reg(df, xcol, ycol)
1 def theil_reg(df, xcol, ycol):
----> 2 model = stats.theilslopes(df[ycol],df[xcol])
3 return pd.Series(model)
C:\Anaconda\lib\site-packages\scipy\stats\_stats_mstats_common.py in theilslopes(y, x, alpha)
248 sigma = np.sqrt(sigsq)
--> 249 Ru = min(int(np.round((nt - z*sigma)/2.)), len(slopes)-1)
250 Rl = max(int(np.round((nt + z*sigma)/2.)) - 1, 0)
ValueError: cannot convert float NaN to integer
During handling of the above exception, another exception occurred:
ValueError Traceback (most recent call last)
<ipython-input-564-d7794bd1d495> in <module>
----> 1 correct_theil = df_accel_correct.groupby('chart').apply(theil_reg, xcol='time', ycol='value')
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in apply(self, func, *args, **kwargs)
699
700 with _group_selection_context(self):
--> 701 return self._python_apply_general(f)
702
703 return result
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in _python_apply_general(self, f)
705 def _python_apply_general(self, f):
706 keys, values, mutated = self.grouper.apply(f, self._selected_obj,
--> 707 self.axis)
708
709 return self._wrap_applied_output(
C:\Anaconda\lib\site-packages\pandas\core\groupby\ops.py in apply(self, f, data, axis)
188 # group might be modified
189 group_axes = _get_axes(group)
--> 190 res = f(group)
191 if not _is_indexed_like(res, group_axes):
192 mutated = True
C:\Anaconda\lib\site-packages\pandas\core\groupby\groupby.py in f(g)
677 def f(g):
678 with np.errstate(all='ignore'):
--> 679 return func(g, *args, **kwargs)
680 else:
681 raise ValueError('func must be a callable if args or '
<ipython-input-563-5db69048f347> in theil_reg(df, xcol, ycol)
1 def theil_reg(df, xcol, ycol):
----> 2 model = stats.theilslopes(df[ycol],df[xcol])
3 return pd.Series(model)
C:\Anaconda\lib\site-packages\scipy\stats\_stats_mstats_common.py in theilslopes(y, x, alpha)
247 # Find the confidence interval indices in `slopes`
248 sigma = np.sqrt(sigsq)
--> 249 Ru = min(int(np.round((nt - z*sigma)/2.)), len(slopes)-1)
250 Rl = max(int(np.round((nt + z*sigma)/2.)) - 1, 0)
251 delta = slopes[[Rl, Ru]]
ValueError: cannot convert float NaN to integer
但是,我在任一列中都没有空值,并且两列都是浮点数。对此错误有何建议?
【问题讨论】:
-
当您将列名从
time更改为foo-bar时会发生什么?它运行了吗? -
@MattR 它有同样的错误:ValueError: could not convert string to float: 'foo-bar'
-
那么至少我们知道它没有将
time作为关键字传递:) -
是和否(我相信)-我尝试将 foo-bar 传递给函数而不更改列名,但它传递了该错误。当我将列名更改为 foo-bar 时,它也传递了同样的错误
-
每当您报告 Python 错误时,请在问题中包含 complete 回溯(即完整的错误消息)。那里有有用的信息,包括究竟是哪一行触发了错误。
标签: python python-3.x pandas scipy linear-regression