【发布时间】:2016-02-15 20:09:43
【问题描述】:
这是我的数据:
> db.bookmarks.find({"userId" : "56b9b74bf976ab70ff6b9999"}).pretty()
{
"_id" : ObjectId("56c2210fee4a33579f4202dd"),
"userId" : "56b9b74bf976ab70ff6b9999",
"items" : [
{
"itemId" : "28",
"timestamp" : "2016-02-12T18:07:28Z"
},
{
"itemId" : "29",
"timestamp" : "2016-02-12T18:07:29Z"
},
{
"itemId" : "30",
"timestamp" : "2016-02-12T18:07:30Z"
},
{
"itemId" : "31",
"timestamp" : "2016-02-12T18:07:31Z"
},
{
"itemId" : "32",
"timestamp" : "2016-02-12T18:07:32Z"
},
{
"itemId" : "33",
"timestamp" : "2016-02-12T18:07:33Z"
},
{
"itemId" : "34",
"timestamp" : "2016-02-12T18:07:34Z"
}
]
}
我想要类似的东西(其实我希望 _id 也可以变成 userId):
{
"_id" : "56b9b74bf976ab70ff6b9999",
"items" : [
{ "itemId": "32", "timestamp": "2016-02-12T18:07:32Z" },
{ "itemId": "31", "timestamp": "2016-02-12T18:07:31Z" },
{ "itemId": "30", "timestamp": "2016-02-12T18:07:30Z" }
]
}
我现在拥有的:
> db.bookmarks.aggregate(
... { $match: { "userId" : "56b9b74bf976ab70ff6b9999" } },
... { $unwind: '$items' },
... { $sort: { 'items.timestamp': -1} },
... { $skip: 2 },
... { $limit: 3},
... { $group: { '_id': '$userId' , items: { $push: '$items.itemId' } } }
... ).pretty()
{ "_id" : "56b9b74bf976ab70ff6b9999", "items" : [ "32", "31", "30" ] }
我尝试在 mongo 中阅读文档并发现我可以 $push,但不知何故我找不到推送此类对象的方法,该对象未在整个对象的任何地方定义。我也想有时间戳..但我不知道我应该如何修改 $group (或其他人??)这样做。感谢您的帮助!
【问题讨论】:
标签: mongodb aggregation-framework