检查文本是否只是十进制数字？

Question

有没有最有效的方法来验证 JavaScript 中的十进制数？

例如如下：

01. IsDec('-7.7')      => true
02. IsDec('-18')    => true
03. IsDec('0')       => true
04. IsDec('.845')    => true
05. IsDec('0.957')     => true
06. IsDec('0x45f')  => false
07. IsDec('15,87')   => false
08. IsDec('#text') => false
09. IsDec('75.95.69')   => false
10. IsDec('')        => false
11. IsDec('someText')    => false

Answer 1

试试这样：

console.log(isDec("-12.5"));
console.log(isDec("12.5"));
console.log(isDec("0"));
console.log(isDec(".45"));
console.log(isDec("1,5"));
console.log(isDec("#ssdr"));

function isDec(txt) {
    return !isNaN(parseFloat(txt)) && isFinite(txt);
}

Answer 2

这是一个用于检查的正则表达式。

/^-?\d*\.?\d*(?<!^\.?)$/

console.log('--- true cases ---');
console.log(isDec('-7.7'));
console.log(isDec('-18'));
console.log(isDec('0'));
console.log(isDec('.845'));
console.log(isDec('0.957'));
console.log(isDec('16.'));

console.log('--- false cases ---');
console.log(isDec('0x45f'));
console.log(isDec('15,87'));
console.log(isDec('#text'));
console.log(isDec('75.95.69'));
console.log(isDec(''));
console.log(isDec('someText'));
console.log(isDec('.'));

function isDec(txt) {
  const regex = /^-?\d*\.?\d*(?<!^\.?)$/;
  return regex.test(txt);
}

查看结果here

Answer 3

请尝试以下检查十进制数的功能

function isDecimal(n) {
   return !isNaN(parseFloat(n)) && isFinite(n);
}

答案：

isDecimal('-7.7')      => true