【发布时间】:2018-06-12 17:43:52
【问题描述】:
我有一个简单的fileUpload rest API,它将上传的文件存储在数据库中,并返回数据库中上传文件的唯一引用(uuid)。
我使用 swagger 来生成 API 文档,它就像一个魅力,但我找不到添加描述文本来描述响应内容的方法。
这是我的 REST 的签名:
@POST
@Path("/upload")
@Consumes(ExtendedMediaType.MULTIPART_FORM_DATA)
@ApiOperation(
value = "Save an image",
notes = "Save the uploaded image to database.",
response = String.class)
@ApiResponses(value = {
@ApiResponse(code = 200, message = "The uploaded image has been saved.", response = String.class),
@ApiResponse(code = 500, message = "Error while trying to resize the image.<p>Internal error code: 2103", response = a.b.ErrorInfo.class)})
@Override
public String uploadImage(
@ApiParam(value = "file to upload", required = true) @FormDataParam("file") final InputStream inputStream,
@ApiParam(value = "details of the uploaded file", required = true) @FormDataParam("file") final FormDataContentDisposition fileDetail) {
//return UUID.randomUUID().toString();
}
我想在 API 文档中添加以下信息,以便描述响应字符串的内容:
"The unique id of the uploaded image."
我查看了ApiResponses 文档,但没有找到与此主题相关的任何内容。
我可以将此信息放在ApiResponse HTTP 200 旁边,但我不确定此解决方案是否正确。
【问题讨论】:
标签: java jersey jax-rs swagger