将数组映射到新数组答案

【问题标题】：Mapping array to new array将数组映射到新数组
【发布时间】：2020-01-18 17:03:08
【问题描述】：

我有一个数组，其中有一个数组，我想为每个“power”数组值创建一个新数组。最好的方法是什么？

原始数组：

Array
(
    [0] => Array
        (
            [date] => 2019-09-16 15:16:03
            [stid] => 64
            [beam] => 1
            [power] => {1,3,7,8,9}
            [gates] => 5
)

   [1] => Array
        (
            [date] => 2019-09-16 15:17:03
            [stid] => 64
            [beam] => 1
            [power] => {14,15,16}
            [gates] => 3
)
)

编辑：输出数组应该从 1 开始递增门

Array
(
    [0] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 1
            [power] => 1
        )

   [1] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 2
            [power] => 3
         )

   [2] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 3
            [power] => 7
         )

   [3] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 4
            [power] => 8
         )


   [4] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 5
            [power] => 9
         )

   [5] => Array
        (
            [date] => 2019-09-16 15:17:03
            [gate] => 1
            [power] => 14
         )

   [6] => Array
        (
            [date] => 2019-09-16 15:17:03
            [gate] => 2
            [power] => 15
         )

   [7] => Array
        (
            [date] => 2019-09-16 15:17:03
            [gate] => 3
            [power] => 16
         )
)

对所有 8（5 和 3）个幂值继续，这样得到的数组是 8 个数组的数组。

【问题讨论】：

标签： php arrays mapping

【解决方案1】：

# Original Data Structure
$arr = 
[
    [
        'date' => '2019-09-16 15:16:03',
        'stid' => 64,
        'beam' => 1,
        'power' => '{1,3,7,8,9}',
        'gates' => 5
    ],
    [
        'date' => '2019-09-16 15:17:03',
        'stid' => 64,
        'beam' => 1,
        'power' => '{14,15,16}',
        'gates' => 3
    ]
];

$output = [];
foreach ($arr as $a)
{
    $gateCount = 0;
    foreach (explode(',', trim($a['power'], '{}')) as $p) 
    {
        $output[] = [
            'date' => $a['date'],
            'gate' => $gateCount++ % $a['gates'] + 1,
            'power' => $p
        ];
    }
}
print_r($output);

输出：

Array
(
    [0] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 1
            [power] => 1
        )

    [1] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 2
            [power] => 3
        )

    [2] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 3
            [power] => 7
        )

    [3] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 4
            [power] => 8
        )

    [4] => Array
        (
            [date] => 2019-09-16 15:16:03
            [gate] => 5
            [power] => 9
        )

    [5] => Array
        (
            [date] => 2019-09-16 15:17:03
            [gate] => 1
            [power] => 14
        )

    [6] => Array
        (
            [date] => 2019-09-16 15:17:03
            [gate] => 2
            [power] => 15
        )

    [7] => Array
        (
            [date] => 2019-09-16 15:17:03
            [gate] => 3
            [power] => 16
        )

)

注意：

['beam'] 和 ['stid'] 根据您的示例已被忽略。如果需要，可以轻松添加。

【讨论】：

这是真的。在我对数据结构的示例重建中，我只是将其设为了一个数组，
我修改了我的答案，让结构使用{x,y} 格式和foreach 相应地。
另外，在这个例子中，门应该等于 0,1,2,3,4,5,0,1,2。我该如何添加？
@mcook16，编辑您的原始问题以指定应如何填充门索引。
@mcook16 您希望如何定义您的'gate'？

【解决方案2】：

你可以这样做：

$newArray = [];
foreach ($oldArray as $element) {
   foreach ($element['power'] as $power) {
      $element['power'] = $power;
      $newArray[] = $element;
   }
}

【讨论】：