用星号匹配 URI

Question

我想做的是自动匹配 URI，并为它们分配正确的描述。假设我有以下 URI：

test
something/action
controller/test
controller/another
controller/action/something
action
action/test
controller/another/somethingelse

它们确实是随机的，但现在我想使用以下数组（数组，因为我认为这将是最好的解决方案）来匹配它们：

$config = array(
     'test' => 'The description of test',
     'something/action' => 'Some action description',
     'controller/another' => 'Another description',
     'controller/action/*' => 'This should match the `controller/action/blah` and everything similar like: `controller/action/something` and give this description'
     'action' => 'Action description',
     'action/*' => 'As the 2nd above, this should match the `action/test` itself, and similar like `action/anothertest` URI
);

这很容易，如果没有星号...（只需 $config[$uri] 以匹配描述）但我也想匹配星号...所以如果有像 controller/another/name 这样的控制器和我会使用像controller/another/* 这样的配置，它会匹配这个数组键的描述。

有人知道怎么做吗？我基本上需要想法，但欢迎任何其他答案！

Answer 1

这可以通过结合fnmatch 和array_filter 之类的东西来完成：

$str=file_get_contents(/*... URIs ...*/);
$config = array(
     'test' => 'The description of test',
     'something/action' => 'Some action description',
     'controller/another' => 'Another description',
     'controller/action/*' => 'This should match the `controller/action/blah` and everything similar like: `controller/action/something` and give this description',
     'action' => 'Action description',
     'action/*' => 'As the 2nd above, this should match the `action/test` itself, and similar like `action/anothertest` URI'
);
foreach(explode("\n",$str) as $line)
{
    $line=trim($line);
    $dkey=array_filter(array_keys($config),function($key)use($line){return fnmatch($key,$line);});
    if(count($dkey)<=0)
    {
        echo "(no description)";
    }
    else
    {
        echo $config[reset($dkey)];
    }
    echo "\n";
}

Online demo

以上代码输出：

The description of test
Some action description
(no description)
Another description
This should match the `controller/action/blah` and everything similar like: `controller/action/something` and give this description
Action description
As the 2nd above, this should match the `action/test` itself, and similar like `action/anothertest` URI
(no description)

上面的代码可以改进：你可以在循环外缓存array_keys结果，这样就不需要一遍又一遍地调用它。

Answer 2

你想要的是.*。 . 在正则表达式 the character class, that matches any character 中（默认情况下，换行符除外），然后您需要 quantifier * 表示匹配任何字符 0 次或更多次。

所以你的正则表达式看起来像

controller/action/.*

匹配

控制器/动作/
控制器/动作/等等
控制器/动作/东西
...

Answer 3

建议的解决方案：

这将返回与 uri 相当的所有描述。这里有改进的余地。干杯！

<?php

    $uris = array(
        'test',
        'something/action',
        'controller/test',
        'controller/another',
        'controller/action/something',
        'action',
        'action/test',
        'controller/another/somethingelse'
    );

    $sUri = $uris[4];
    print_r(
        getConfigBasedOnKey($sUri)
    );

    function getConfigBasedOnKey($sUri) {

        $config = array(
             'test' => 'The description of test',
             'something/action' => 'Some action description',
             'controller/another' => 'Another description',
             'controller/action/*' => 'This should match the controller/action/blah and everything similar like: controller/action/something and give this description',
             'action' => 'Action description',
             'action/*' => 'As the 2nd above, this should match the `action/test` itself, and similar like action/anothertest URI'
        );

        $descriptions = array();
        foreach($config as $configKey => $configDescription) {
            $configKey = preg_replace("/\*/",".*",$configKey);

            preg_match("|^$configKey$|",$sUri,$matches);
            if(count($matches) > 0) {
                $descriptions[] = $configDescription;
            }
        }

        return $descriptions;
    }

?>

输出：

Array
(
    [0] => This should match the controller/action/blah and everything similar like: controller/action/something and give this description
)