【发布时间】:2018-06-12 17:35:15
【问题描述】:
我是一名应届毕业生,我是第一次学习 Codeigniter,我遇到了困难,请帮助我解决我的问题。我创建了一个记录员工信息的系统。我在我的代码中包含了实时搜索。语法没有错误,但没有显示结果。下面是我的代码。
这里是控制器。它的文件名是 Crud.php
控制器
public function fetch()
{
$output = '';
$query = '';
if($this->input->post('query'))
{
$query = $this->input->post('query');
}
$data = $this->Crudmodel->fetch();
$output .= '
<div class="table-responsive">
<table class="table table-bordered">
<tr>
<th>First Name</th>
<th>Last Name</th>
<th>Job Title</th>
</tr>
';
if($data->num_rows() > 0)
{
foreach($data->result() as $row)
{
$output .= '
<tr>
<td>'.$row->fname.'</td>
<td>'.$row->lname.'</td>
<td>'.$row->job_title.'</td>
</tr>
';
}
}
else
{
$output .= '<tr>
<td colspan="5">No Data Found</td>
</tr>';
}
$output .= '</table>';
echo $output;
}
这是模型。文件名:Crudmodel.php
型号
public function fetch_data($query){
$this->db->select("*");
$this->db->from("employees");
if($query != ''){
$this->db->or_like('fname', $query);
$this->db->or_like('lname', $query);
$this->db->or_like('job_title', $query);
}
$this->db->order_by('id');
return $this->db->get();
}
查看
<!DOCTYPE html>
<html lang="en" dir="ltr">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title></title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
</head>
<body>
<div class="row">
<div class="col-lg-12 margin-tb">
<div class="pull-left">
<h2>Employee Registation</h2>
</div><br>
<div class="pull-right">
<a class="btn btn-success" href="<?php echo base_url('crud/create') ?>"> Add Employee</a>
<a type="button" class="btn btn-danger" href="crud/logout">Logout</a>
</div>
</div>
</div>
<div class="form-group">
<div class="input-group">
<span class="input-group-addon">Search</span>
<input type="text" name="search_text" id="search_text" placeholder="Search Employee" class="form-control" />
</div>
</div>
<div id="result"></div>
<div style="clear:both"></div>
<table class="table table-bordered">
<thead>
<tr>
<!-- <th>Full Name</th> -->
<th>First Name</th>
<th>Last Name</th>
<th>Job Title</th>
<th width="220px">Action</th>
</tr>
</thead>
<tbody>
<?php foreach ($data as $employees)
{
?>
<tr>
<td> <?php echo $employees->fname; ?></td>
<td> <?php echo $employees->lname; ?></td>
<td> <?php echo $employees->job_title; ?></td>
<td>
<form method="DELETE" action="<?php echo base_url('crud/delete/'.$employees->id); ?>">
<a class="btn btn-info" href="<?php echo base_url('crud/show/'.$employees->id) ?>"> View</a>
<a class="btn btn-primary" href="<?php echo base_url('crud/edit/'.$employees->id) ?>"> Edit</a>
<button type="submit" class="btn btn-danger"> Delete</button>
</form>
</td>
</tr>
<?php } ?>
</tbody>
</table>
</body>
</html>
<script>
$(document).ready(function () {
load_data();
function load_data(query)
{
$.ajax({
url: "<?php echo base_url('crud/fetch'); ?>",
method: "POST",
data: {query: query},
success: function (data) {
$('#result').html(data);
}
})
}
$('#search_text').keyup(function () {
var search = $(this).val();
if (search != '')
{
load_data(search);
} else
{
load_data();
}
});
});
</script>
请帮我弄清楚。您的帮助将不胜感激!
【问题讨论】:
-
您必须使用
like,如此处所述w3schools.com/sql/sql_like.asp
标签: php codeigniter codeigniter-3 livesearch