mysql查询计算like运算符匹配每列的次数

Question

$sql ="SELECT * 
       FROM members m 
       INNER JOIN author_details a 
          on m.email= a.email 
       where m.name like '".$search_text."%' 
          or a.username like '".$search_text."%' 
          or a.address_line1 like '%".$search_text."%' 
          or a.address_line2 like '%".$search_text."%' 
          or a.city like '%".$search_text."%' 
          or m.phone = ".(int)$search_text."

所以我正在寻找的是计算哪一列的匹配度最高，然后首先返回该结果集，例如，如果在地址列中找到关键字最匹配，那么结果集现在应该首先包含地址匹配的结果，结果是即使他们很少，也会首先显示名称。

我对 sql 不太了解，所以请尽量保持简单

Answer 1

比较运算符在匹配时返回1，因此您可以使用SUM() 将它们相加。

$sql ="SELECT
            SUM(m.name like '".$search_text."%') AS name_matches,
            SUM(a.username like '".$search_text."%') AS username_matches,
            SUM(a.address_line1 like '%".$search_text."%') AS addr1_matches,
            SUM(a.address_line2 like '%".$search_text."%') AS addr2_matches,
            SUM(a.city like '%".$search_text."%') AS city_matches,
            SUM(m.phone = ".(int)$search_text.") AS phone_matches
       FROM members m 
       INNER JOIN author_details a 
          on m.email= a.email";

_matches 中的每一列都将包含搜索文本在该列中匹配的行数。