【问题标题】:How to read multiple child node and get the value如何读取多个子节点并获取值
【发布时间】:2017-06-30 07:20:52
【问题描述】:

这是我要解析的 Xml

  </Worker><Worker>
    <Employee_ID>12349294</Employee_ID>
    <Position_ID>50099501</Position_ID>
    <Process>
        <Bp_Type>Hire</Bp_Type>
        <Status>Pass</Status>
    </Process>
    <Process>
        <Bp_Type>Leave of Absence</Bp_Type>
        <Status>Fail</Status>
        <Fault_String>Validation error occurred. Invalid ID value.  'LEAVE_TYPE_ACCOMODATION_ACCOMODATION' is not a valid ID value for type = 'Leave_of_Absence_Type_ID'</Fault_String>
    </Process>

    <Process>
        <Bp_Type>Non Effective Dated Worker Additional Data</Bp_Type>
        <Status>Pass</Status>
    </Process>

    </Worker><Worker>
    <Worker>
    <Employee_ID>12349386</Employee_ID>
    <Position_ID>50279490</Position_ID>
    <Process>
        <Bp_Type>Hire</Bp_Type>
        <Status>Fail</Status>
        <Fault_String>Validation error occurred. You can't assign a Military Status to a worker when their Hire Date is before the Effective Date of the Location</Fault_String>
    </Process>
    /Worker>

这里我正在尝试根据状态解析 xml 文件。我需要收集所有“失败”状态,这是我正在检查下面的代码。它适用于第二个节点。但它不适用于有两个子节点的第一个节点。任何建议都会有所帮助

 for(int i=0;i<sourceDir.length;i++){
 Document doc = docBuilder.parse(sourceDir[i]);

 // normalize text representation
 doc.getDocumentElement().normalize();

 NodeList nList = doc.getElementsByTagName("Worker");
 int totalPersons = nList.getLength();

 for (int s = 0; s < nList.getLength(); s++) {

 Node nNode = nList.item(s);
 Element eElement = (Element) nNode;


 if (nNode.getNodeType() == Node.ELEMENT_NODE) {

 if( eElement.getElementsByTagName("Status")!=null && eElement.getElementsByTagName("Status").item(0)!=null                                                 &&eElement.getElementsByTagName("Status").item(0).getTextContent().equals("Fail") ){

 NodeList nEmp = eElement.getElementsByTagName("Employee_ID");
 Element eId = (Element) nEmp.item(0);
 NodeList textFNList = eId.getChildNodes();
                                                        System.out.println("Employee_ID : "+ ((Node)    textFNList.item(0)).getNodeValue().trim());
  empID.add(((Node) textFNList.item(0)).getNodeValue().trim());

  NodeList nStatus = eElement.getElementsByTagName("Status");
  Element eStatus = (Element) nStatus.item(0);
  NodeList textLNList = eStatus.getChildNodes();

  System.out.println("Status : "+ ((Node) textLNList.item(0)).getNodeValue().trim());
  status.add(((Node) textLNList.item(0)).getNodeValue().trim());

  NodeList nFault = eElement.getElementsByTagName("Fault_String");
  Element eFault = (Element) nFault.item(0);
  NodeList textAgeList = eFault.getChildNodes();
  System.out.println("Fault_String"+ ((Node) textAgeList.item(0)).getNodeValue().trim());
 fault_String.add(((Node) textAgeList.item(0)).getNodeValue().trim());

                        }
                   }
            }




     }

【问题讨论】:

    标签: java xml dom


    【解决方案1】:

    您好,您可以按照以下代码获得答案。此代码将解决您的问题


        DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
        try {
            DocumentBuilder dBuilder  = dbFactory.newDocumentBuilder();
            Document doc = dBuilder.parse(new File("FileLocation"));
            doc.getDocumentElement().normalize();
            System.out.println("Root element :" 
                    + doc.getDocumentElement().getNodeName());
            NodeList nList = doc.getElementsByTagName("Worker");
            int totalPersons = nList.getLength();
            for (int s = 0; s < nList.getLength(); s++) {
                    Node nNode = nList.item(s);
                    Element eElement = (Element) nNode;
                    if (nNode.getNodeType() == Node.ELEMENT_NODE) {
                    NodeList processesList = eElement.getElementsByTagName("Process");                  for (int i = 0; i < processesList.getLength(); i++) {
                        Node node = processesList.item(i);
                        Element element = (Element) node;
                        if( element.getElementsByTagName("Status")!=null && element.getElementsByTagName("Status").item(0)!=null
                                &&element.getElementsByTagName("Status").item(0).getTextContent().equals("Fail") ){
    
                                NodeList nEmp = eElement.getElementsByTagName("Employee_ID");
                                Element eId = (Element) nEmp.item(0);
                                NodeList textFNList = eId.getChildNodes();
    
                                System.out.println("Employee_ID : "+ ((Node) textFNList.item(0)).getNodeValue().trim());
                                empID.add(((Node) textFNList.item(0)).getNodeValue().trim());
    
                                NodeList nStatus = element.getElementsByTagName("Status");
                                Element eStatus = (Element) nStatus.item(0);
                                NodeList textLNList = eStatus.getChildNodes();
    
                                System.out.println("Status : "+ ((Node) textLNList.item(0)).getNodeValue().trim());
                                status.add(((Node) textLNList.item(0)).getNodeValue().trim());
    
                                NodeList nFault = element.getElementsByTagName("Fault_String");
                                Element eFault = (Element) nFault.item(0);
                                if(eFault != null){
                                NodeList textAgeList = eFault.getChildNodes();
                                System.out.println("Fault_String"+ ((Node) textAgeList.item(0)).getNodeValue().trim());
                                fault_String.add(((Node) textAgeList.item(0)).getNodeValue().trim());
                                }else{
                                    fault_String.add("");
                                }
                            }
    
                    }
    
                }
            }
        } catch (ParserConfigurationException | SAXException | IOException e) {
            e.printStackTrace();
        }
    

    【讨论】:

    • 没有解释你是如何解决他的问题的,也许可以具体说明一下。
    • Ok.. 在前面的代码中,您没有检查 Process 标签的所有值。我必须检查所有进程标签的状态值。在我的代码中,我只是通过获取进程标签的数量来检查所有进程。
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