T-SQL 将二级 XML 节点分解为多行

Question

我觉得这应该是很简单的事情，但我似乎无法弄清楚。

给定以下 XML：

<Responses>
  <Response>
    <ResponseId>1</ResponseId>
    <DateCreated>2016-02-01T18:26:17Z</DateCreated>
    <Detail>
      ...
    </Detail>
  </Response>
  <Response>
    <ResponseId>2</ResponseId>
    <DateCreated>2016-02-01T18:33:28Z</DateCreated>
    <Detail>
      ...
    </Detail>
  </Response>
  <Response>
    <ResponseId>3</ResponseId>
    <DateCreated>2016-02-12T19:33:48Z</DateCreated>
    <Detail>
      ...
    </Detail>
  </Response>
  <Response>
    <ResponseId>4</ResponseId>
    <DateCreated>2016-02-15T18:21:09Z</DateCreated>
    <Detail>
      ...
    </Detail>
  </Response>
  <Response>
    <ResponseId>5</ResponseId>
    <DateCreated>2016-02-15T19:04:07Z</DateCreated>
    <Detail>
      ...
    </Detail>
  </Response>
</Responses>

我期待如下结果：

我能够很好地检索每个节点的元素（即 ResponseId、DateCreated 和 Detail 导致五行，每行 3 列），但我需要返回完整的响应节点 xml。

目前，我能想到的唯一解决方案是在检索 ResponseId、DateCreated 和 Detail 后手动重新构建所需的结果，但这对我来说似乎是一个混乱且容易出错的选项。

Answer 1

您可以使用.nodes() 和.query()

DECLARE @xml XML=
N'<Responses>
  <Response>
    <ResponseId>1</ResponseId>
    <DateCreated>2016-02-01T18:26:17Z</DateCreated>
    <Detail>
    </Detail>
  </Response>
  <Response>
    <ResponseId>2</ResponseId>
    <DateCreated>2016-02-01T18:33:28Z</DateCreated>
    <Detail>
    </Detail>
  </Response>
  <Response>
    <ResponseId>3</ResponseId>
    <DateCreated>2016-02-12T19:33:48Z</DateCreated>
    <Detail>
    </Detail>
  </Response>
  <Response>
    <ResponseId>4</ResponseId>
    <DateCreated>2016-02-15T18:21:09Z</DateCreated>
    <Detail>
    </Detail>
  </Response>
  <Response>
    <ResponseId>5</ResponseId>
    <DateCreated>2016-02-15T19:04:07Z</DateCreated>
    <Detail>
    </Detail>
  </Response>
</Responses>';

--选择

SELECT One.Resp.query(N'.')
FROM @xml.nodes(N'/Responses/Response') AS One(Resp)