通过标签名称获取 xml 元素答案

【问题标题】：Getting xml elements by tag name通过标签名称获取 xml 元素
【发布时间】：2019-05-05 13:53:31
【问题描述】：

我在这里看到了几乎所有关于这个问题的问题，但没有一个是相关的。

$employees = simplexml_load_string($response)->c->q[1]['v'];

$employees = SimpleXML 对象：

<?xml version="1.0" encoding="utf-8" ?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
    <row id="1">
        <EmployeeID>
            <![CDATA[123]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[John Doe]]>
        </EmplopyeeName>
    </row>
    <row id="2">
       <EmployeeID>
            <![CDATA[456]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[Jack Mill]]>
        </EmplopyeeName>
    </row>
</rows>

我想检索所有员工（如果找到）。

我尝试使用以下方式访问它们：

$employees->children() [空数组]
$employees->rows [空数组]
$employees->row [空数组]
$employees->xpath('//rows') [空数组]
$employees->xpath('//row') [空数组]
$employees->registerXPathNamespace('x', 'http://www.w3.org/2001/XMLSchema-instance'); $employees->xpath('//x:row') [空数组]

var_dump($employees->getName()); //returns "v"

var_dump($employees->getNamespaces()); //returns NULL

var_dump($employees); 返回：

object(SimpleXMLElement)#26 (1) {
  [0]=>
  string(xxx) "
<?xml version="1.0" encoding="utf-8" ?>
    <rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
        <row id="1">
            <EmployeeID>
                <![CDATA[123]]>
            </EmployeeID>
            <EmplopyeeName>
                <![CDATA[John Doe]]>
            </EmplopyeeName>
        </row>
        <row id="2">
           <EmployeeID>
                <![CDATA[456]]>
            </EmployeeID>
            <EmplopyeeName>
                <![CDATA[Jack Mill]]>
            </EmplopyeeName>
        </row>
    </rows>"
}

有人能指出导致问题的原因吗？

【问题讨论】：

标签： php xml simplexml xml-namespaces

【解决方案1】：

这对我有用：

<?php

$employees =<<< EMP
<?xml version="1.0" encoding="utf-8" ?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
    <row id="1">
        <EmployeeID>
            <![CDATA[123]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[John Doe]]>
        </EmplopyeeName>
    </row>
    <row id="2">
       <EmployeeID>
            <![CDATA[456]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[Jack Mill]]>
        </EmplopyeeName>
    </row>
</rows>
EMP;

$employees = simplexml_load_string($employees);
foreach($employees->row as $row)
{
   print((string) $row->EmployeeID);
   print((string) $row->EmplopyeeName);
}

为您的情况尝试的东西：

$employeeXml = simplexml_load_string((string) $employees);
foreach($employeeXml->row as $row)
{
   print((string) $row->EmployeeID);
   print((string) $row->EmplopyeeName);
}

【讨论】：

就我而言：var_dump($employees->row); //returns object(SimpleXMLElement)#26 (0) { }
Employees 最初是从 API Response 返回的 ===> $employees = simplexml_load_string($response)->c->q[1]['v'];

【解决方案2】：

你可以这样处理

$xml = <<< EMP
<?xml version="1.0" encoding="utf-8" ?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
<row id="1">
    <EmployeeID>
        <![CDATA[123]]>
    </EmployeeID>
    <EmplopyeeName>
        <![CDATA[John Doe]]>
    </EmplopyeeName>
</row>
 <row id="2">
   <EmployeeID>
        <![CDATA[456]]>
    </EmployeeID>
    <EmplopyeeName>
        <![CDATA[Jack Mill]]>
    </EmplopyeeName>
 </row>
</rows>
EMP;
$xmlToArray = json_decode(json_encode((array)simplexml_load_string($xml,null,LIBXML_NOCDATA)),true);
foreach($xmlToArray['row'] as $row){
 echo trim($row['EmployeeID']).'---'.trim($row['EmplopyeeName']);
}

DEMO LINK

【讨论】：