Golang - 使用更改键值解组 JSON答案

【问题标题】：Golang - Unmarshall JSON with changing key valueGolang - 使用更改键值解组 JSON
【发布时间】：2016-08-05 16:57:05
【问题描述】：

我正在尝试将 JSON 解组为一个结构，但事实证明这很困难，因为外部 JSON 键发生了变化，而我一周前才开始使用。这是我的手动尝试：

import (
    "encoding/json"
    "fmt"
    "strconv"
)

type Device struct {
    localUUID       string
    applicationUUID string
    externalUUID    string
    commit          string
    lastSeen        string
    state           string
    progress        float32
}

func main() {
    devices := make([]*Device, 0, 10)

    b := []byte(`{
        "5417871461137421886": {
            "applicationUUID": "test_applicationUUID",
            "commit": "test_commit",
            "lastSeen": "test_lastSeen",
            "localUUID": "E4:F5:13:8E:F5:43",
            "progress": "3.5",
            "externalUUID": "test_externalUUID",
            "state": "test_state"
        },
        "5632882567440442530": {
            "applicationUUID": "test_applicationUUID",
            "commit": "test_commit",
            "lastSeen": "test_lastSeen",
            "localUUID": "E4:F5:13:8E:F5:42",
            "progress": "3.5",
            "externalUUID": "test_externalUUID",
            "state": "test_state"
        },
        "8912255216147730520": {
            "applicationUUID": "test_applicationUUID",
            "commit": "test_commit",
            "lastSeen": "test_lastSeen",
            "localUUID": "E4:F5:13:8E:F5:41",
            "progress": "3.5",
            "externalUUID": "test_externalUUID",
            "state": "test_state"
        }
    }`)

    var f interface{}
    json.Unmarshal(b, &f)
    outer := f.(map[string]interface{})
    for _, value := range outer {
        inner := value.(map[string]interface{})
        device := &Device{}
        device.localUUID = inner["localUUID"].(string)
        device.applicationUUID = inner["applicationUUID"].(string)
        device.externalUUID = inner["externalUUID"].(string)
        device.commit = inner["commit"].(string)
        device.lastSeen = inner["lastSeen"].(string)
        device.state = inner["state"].(string)
        f, _ := strconv.ParseFloat(inner["progress"].(string), 32)
        device.progress = float32(f)

        devices = append(devices, device)
    }

    for _, device := range devices {
        fmt.Println(device)
    }
}

有没有办法忽略键并迭代值，允许我使用 json.Unmarshal(b, &Device)？

【问题讨论】：

标签： json go struct unmarshalling

【解决方案1】：

您有一系列 JSON 对象，映射到每个 Device 的唯一 ID。将其解组为map

type Device struct {
    LocalUUID       string  `json:"localUUID"`
    ApplicationUUID string  `json:"applicationUUID"`
    ExternalUUID    string  `json:"externalUUID"`
    Commit          string  `json:"commit"`
    LastSeen        string  `json:"lastSeen"`
    State           string  `json:"state"`
    Progress        float32 `json:"progress,string"`
}

func main() {
    devices := make(map[string]*Device)

    err := json.Unmarshal(b, &devices)
    if err != nil {
        log.Fatal(err)
    }

    for _, device := range devices {
        fmt.Printf("%#v\n", device)
    }
}

https://play.golang.org/p/JDZzG64jJR

【讨论】：

谢谢。我知道肯定有更简单的方法。