在 Teradata SQL 中选择给定系列中的 ID

Question

如何选择系列后面的id，例如对于每个id， 当条件1为11,12,13，对应条件2为null,14,16.

数据如下

id      condition1  condition2
101       11          ? 
101       13          14    
101       15          16
102       11          ?
102       13          14
102       15          16
102       17          18
103       13          14
103       15          16
104       11          ? 
104       13          14
104       15          16
104       13          14
104       15          16
105       11          ?
105       13          14

预期输出

id      condition1  condition2
101       11          ? 
101       13          14    
101       15          16
103       13          14
103       15          16
104       11          ? 
104       13          14
104       15          16
104       13          14
104       15          16

提前谢谢你

Answer 1

编辑以匹配您的新逻辑。

如果没有重复行：

select *
from tab
qualify
   sum(case when condition1 = 11 and condition2 is null
            then 0 -- ignore it
            when condition1 = 13 and condition2 = 14
              or condition1 = 15 and condition2 = 16
            then  1 -- increase for specific rows
            else -1 -- decrease for any other row
        end)
   over (partition by id) = 2

不幸的是，Windowed Aggregates 不支持 DISTINCT，但有一个解决方法，只检查第一行：

select *
from 
 (
   select t.*
     ,row_number() -- check 1st row only
      over (partition by id, condition1, condition2
            order by id) as rn
   from tab as t
 ) as dt
qualify
   sum(case when rn = 1 -- check 1st row only
             and condition1 = 11 and condition2 is null
            then 0 -- ignore it
            when rn = 1 
             and (condition1 = 13 and condition2 = 14
               or condition1 = 15 and condition2 = 16)
            then  1 -- increase for specific rows
            else -1 -- decrease for any other row
        end)
   over (partition by id) = 2