我想根据odoo中另一个模型中的状态更新模型中的状态

Question

我想根据 odoo 中另一个模型中的状态更新模型中的状态。

我尝试在员工模型中更新员工状态：

where work_order_state= "progress" set employee_state="unavailable"

我尝试 onchange 函数但它使用较少并尝试更新函数但它不返回任何内容并尝试更新/创建相同的东西 这是我在堆栈溢出中的第一个问题，任何人都可以帮助我。

Python：

from typing import ByteString
from odoo import models, fields, api,exceptions, _
from odoo.exceptions import ValidationError, UserError

""" Defines manufacturing resource """

class MrpWorkcenter(models.Model):
    _inherit = 'mrp.workcenter'
    _description = 'Work Center'
    
    employee_ids = fields.One2many('hr.employee', 'employee_id', string="Resource")
    
    workcenter_id = fields.Many2one("mrp.workorder")  
    employee_id = fields.Many2one('hr.employee', string="Name")
    resource_state = fields.Many2one('hr.employee', string="State")  

class Employee(models.Model):
    _inherit = "hr.employee"
    _description = "Employee"

   
    is_resource = fields.Boolean('Resource')
    employee_id = fields.Many2one('mrp.workcente', string="Resource")
    resource_state = fields.Selection([
        ('available', 'Available'),
        ('unavailable', 'Unavailable')],
         string='State')
    workcenter_ids = fields.One2many("mrp.workcenter", 'employee_id',string="Work Center")
    workorder_id = fields.Many2one("mrp.workorder", string="Resource")


    @api.multi
    def _update_state(self, vals):
        for res in self:
            record_to_update= self.env['hr.employee'].search()
            if record_to_update.exists():
                for rtn in self:
                    record_to_search= self.env['mrp.workorder'].search([('state', '=','progress')])
                    if record_to_search.exists():
                        vals={
                        'resource_state':'unavailable'
                            }
                        record_to_update.write(vals)
                        return rtn

        return res

class ManufacurWorkorder(models.Model):
    _inherit = 'mrp.workorder'
    _description = 'Work Order'

            
    workcenter_id = fields.Many2one("mrp.workcenter")
    employee_ids = fields.Many2many('hr.employee', string="Resource")
    state = fields.Selection([
        ('pending', 'Pending'),
        ('ready', 'Ready'),
        ('progress', 'In Progress'),
        ('done', 'Finished'),
        ('cancel', 'Cancelled')], string='Status',
        default='pending')
    workorder_id = fields.Many2one('mrp.workorder')

XML：

<?xml version="1.0" encoding="utf-8"?>
<odoo>
  <data>

    <!-- Created by Mehad Mregany at 01022021 10:30 am -->
     <!-- Edited  by Mehad Mregany at 07022021 08:30 am -->

                 <!-- Manufacture Resource -->

<record id="manufacture_resource_hr_form_id" model="ir.ui.view">
    <field name="name">hr.employee.form</field>
    <field name="model">hr.employee</field>
    <field name="inherit_id" ref="hr.view_employee_form"/>
    <field name="arch" type="xml">
        <field name="mobile_phone"  position="replace">
            <field name="is_resource"/>
        </field>
        <field name="work_phone" position="replace">
            <field name="resource_state" attrs="{'invisible':[('is_resource', '=', False)]}"/>
        </field>
        <field name="coach_id" position="replace">
              <field name="workcenter_ids" widget="many2many_tags"
               attrs="{'invisible':[('is_resource', '=', False)]}"
               options="{'no_create':True,'no_create':True }"/>
        </field>
    </field>
</record>

<record id="manufacture_resource_hr_tree_id" model="ir.ui.view">
          <field name="name">hr.employee.tree</field>
          <field name="model">hr.employee</field>
          <field name="inherit_id" ref="hr.view_employee_tree"/>
          <field name="arch" type="xml">
              <field name="name" position="after">
                  <field name="is_resource"/>
              </field>
               <field name="work_phone" position="replace">
                  <field name="resource_state"/>
              </field>
          </field>
</record>

<record id="manufacture_resource_workorder_form_id" model="ir.ui.view">
    <field name="name">mrp.workorder.form</field>
    <field name="model">mrp.workorder</field>
    <field name="inherit_id" ref="mrp.mrp_production_workcenter_form_view_inherit"/>
    <field name="arch" type="xml">
    
    <notebook>
     <page string="Resource">
        <field name="employee_ids" 
        domain="[('resource_state','=','available'), ('is_resource','=','True')]">
            <tree string="Resource" editable="bottom"> 
                <field string="Employee" name="name" />               
            </tree>
        </field>
     </page>
    </notebook>
    </field>
</record>

  </data>
</odoo>

Answer 1

正如我从您的分布式代码中得到的那样，您希望在 mrp.workorder 中更新基于 hr.employee 的状态 你可以更新你的代码看起来像这样首先将你的代码移动到 mrp.workorder

@api.onchange('state')
def update_state(self, vals):
    record_to_update= self.env['hr.employee'].search([('employee_id', 'in', self.employee_ids)])
    if record_to_update and self.state == 'progress':
        self.env['hr.employee'].write({'resource_state': 'unavailable'})