如何在Python中获取两个日期之间特定月份的天数答案

【问题标题】：How to get the number of Days in a Specific Month between Two Dates in Python如何在Python中获取两个日期之间特定月份的天数
【发布时间】：2017-08-22 11:33:22
【问题描述】：

我有两个日期字段 campaign_start_date 和 campaign_end_date。我想计算每个月介于campaign_start_date 和campaign_end_date 之间的天数。

例如：

campaign_start_date  = September 7 2017
campaign_end_date    = November 6 2017

解决方案应该是：

Total No:of days       = 61 days
No: of months          = 3 months
Month 1                = 9/7/2017 to 9/30/2017
Month 2                = 10/1/2017 to 10/31/2017
Month 3                = 11/1/2017 to 11/6/2017
No:of days in Month 1  = 24 days
No:of days in Month 2  = 31 days
No:of days in Month 3  = 6 days

如何使用 Python 实现这一点？到目前为止，我已经取得了：

@api.multi
    def print_date(self):
        start_date = datetime.strptime(self.start_date, "%Y-%m-%d %H:%M:%S")
        end_date = datetime.strptime(self.end_date, "%Y-%m-%d %H:%M:%S")
        campaign_start_date = date(start_date.year,start_date.month,start_date.day)
        campaign_end_date = date(end_date.year,end_date.month,end_date.day)
        duration = (campaign_end_date-campaign_start_date).days  
        return True

【问题讨论】：

我得到了总天数

标签： python-2.7 ubuntu odoo-10 odoo-accounting

【解决方案1】：

以天为单位计算持续时间：

from datetime import date

campaign_start_date = date(2017, 9, 7)
campaign_end_date = date(2017, 10, 6)
duration = (campaign_end_date-campaign_start_date).days
print campaign_start_date, campaign_end_date, duration

进一步计算的一些提示：

import calendar

campaign_end_month_start = campaign_end_date.replace(day=1)
days_in_month_campaign_end = (campaign_end_date - campaign_end_month_start).days + 1

range_startmonth = calendar.monthrange(campaign_start_date.year, campaign_start_date.month)
campaign_start_month_ends = campaign_start_date.replace(day=range_startmonth[1])

days_in_month_campaign_begins = (campaign_start_month_ends - campaign_start_date).days

通过这种方式，您可以计算活动每个月的天数（请注意检查 campaign_end_date 是否在另一个月份而不是 campaign_start_date

对于计算，您还可以访问日期字段，例如

campaign_start_date.day
campaign_start_date.month
campaign_start_date.year

要计算您的广告系列中涉及的月份数并获取月份列表以计算每月持续时间，您可以使用它（基于 Python: get all months in range? 中 m.antkowicz 的回答）。在循环之前和循环内将日期设置为 1 (current = current.replace(day=1)) 很重要，否则当您的开始日期是一个月的 31 日并且下个月短于 31 天或者如果您有更长的时间段时，您会跳过一个月：

from datetime import date, datetime, timedelta    
current = campaign_start_date
result = [current]

current = current.replace(day=1)
while current <= campaign_end_date:
    current += timedelta(days=32)
    current = current.replace(day=1)
    result.append(datetime(current.year, current.month, 1))

print result, len(result)

哪个打印（当你使用current.strftime('%Y-%m-%d'):

['2017-09-07', '2017-10-01', '2017-11-01'] 3

现在您可以遍历结果列表并计算每月的天数：

durations= []
for curr in result:
    curr_range = calendar.monthrange(curr.year, curr.month)
    curr_duration = (curr_range[1] - curr.day)+1
    if (curr.month < campaign_end_date.month):
        durations.append(curr_duration)
    else:
        durations.append(campaign_end_date.day)

print durations

它为您提供所需的“第 x 个月的天数”作为列表：

[24, 31, 6]

【讨论】：

感谢您花时间回答我的问题，这真的很有帮助。
它适用于同一年的日期。对于不同年份的日期，它会在“持续时间”中给出错误的结果。此外，它在 end_date 之后提供了额外的一个月。添加了一种对所有日期都有效的方法

【解决方案2】：

这是处理不同年份日期的强大解决方案。

def get_months_and_durations(start_date,end_date):
    current = start_date
    result = [current]

    current = current.replace(day=1)
    while current <= end_date:
        current += timedelta(days=32)
        current = current.replace(day=1)
        result.append(datetime(current.year, current.month, 1).date())

    durations= []
    for curr in result[:-1]:
        curr_range = calendar.monthrange(curr.year, curr.month)
        curr_duration = (curr_range[1] - curr.day)+1

        if ((curr.month == end_date.month) & (curr.year == end_date.year)):
            durations.append(end_date.day)
        else:
            durations.append(curr_duration)
    return result[:-1],durations

【讨论】：