SQL XML 查询模式？答案

【问题标题】：SQL XML Query Pattern?SQL XML 查询模式？
【发布时间】：2012-01-23 03:54:32
【问题描述】：

我在一个 141k XML 文档中有一些如下所示的 XML。谁能展示一个 SQL Server 2008 XQuery 来将它插入两个临时表，一个具有“州”子关系的“国家”表？

谢谢。

<?xml version="1.0" encoding="utf-8"?>
<countries author="Michael John Grove" title="Country, State-Province selections"
date="2008-Feb-05">
  <country name="Afghanistan">
    <state>Badakhshan</state>
    <state>Badghis</state>
    <state>Baghlan</state>
    </country>
  <country name="Albania">
    <state>Berat</state>
    <state>Bulqize</state>
    <state>Delvine</state>

    etc

【问题讨论】：

标签： xml sql-server-2008 tsql xpath xquery

【解决方案1】：

以整数标识列作为主键的版本。

declare @Country table
(
  CountryID int identity primary key,
  Name varchar(50)
)

declare @State table
(
  StateID int identity primary key,
  CountryID int,
  Name varchar(50)
)

insert into @Country (Name)
select C.C.value('@name', 'varchar(50)')
from @xml.nodes('/countries/country') as C(C)

insert into @State (CountryID, Name)
select Country.CountryID, S.S.value('.', 'varchar(50)')
from @xml.nodes('/countries/country') as C(C)
  cross apply C.C.nodes('state') as S(S)
  inner join @Country as Country
    on Country.Name = C.C.value('@name', 'varchar(50)')

Working sample on SE Data

还有一个使用名称作为主键的版本。

declare @Country table
(
  CountryName varchar(50) primary key
)

declare @State table
(
  StateName varchar(50) primary key,
  CountryName varchar(50)
)

insert into @Country (CountryName)
select distinct C.C.value('@name', 'varchar(50)')
from @xml.nodes('/countries/country') as C(C)

insert into @State (StateName, CountryName)
select S.S.value('.', 'varchar(50)'), 
       C.C.value('@name', 'varchar(50)')
from @xml.nodes('/countries/country') as C(C)
  cross apply C.C.nodes('state') as S(S)

【讨论】：

【解决方案2】：

试试这个：

declare @x xml = '<?xml version="1.0" encoding="utf-8"?>
<countries author="Michael John Grove" title="Country, State-Province selections"
date="2008-Feb-05">
  <country name="Afghanistan">
    <state>Badakhshan</state>
    <state>Badghis</state>
    <state>Baghlan</state>
    </country>
  <country name="Albania">
    <state>Berat</state>
    <state>Bulqize</state>
    <state>Delvine</state>
  </country>
</countries>'

declare @StateTable table(StateId int, [State] nvarchar(100))
declare @CountryTable table(CountryId int, [Country] nvarchar(100))
declare @CountryState table(CountryId int, StateId int)

declare @tempTable table(StateId int, [State] nvarchar(100), CountryId int, [Country] nvarchar(100))

insert @tempTable
    select ROW_NUMBER() over(order by ta.[state], ta.country) [stateId]
        , ta.state
        , DENSE_RANK() over(order by ta.country) [countryId]
        , ta.country
    from
    (
        select t.s.value('.', 'nvarchar(100)') [state]
            , t.s.value('../@name', 'nvarchar(100)') [country]
        from @x.nodes('countries/country/state') t(s)
    )ta


insert @StateTable
    select c.stateId, c.state
    from @tempTable c

insert @CountryTable
    select distinct c.countryId, c.country
    from @tempTable c

insert @CountryState
    select c.countryId, c.stateId
    from @tempTable c

select * from @StateTable
select * from @CountryTable
select * from @CountryState

输出：

StateId     State
----------- -----------
1           Badakhshan
2           Badghis
3           Baghlan
4           Berat
5           Bulqize
6           Delvine


CountryId   Country
----------- -----------
1           Afghanistan
2           Albania


CountryId   StateId
----------- -----------
1           1
1           2
1           3
2           4
2           5
2           6

【讨论】：

【解决方案3】：

我建议对这项任务使用 XML 批量加载 (SQLXML 4.0)。过程将是这样的： 1.创建临时表 2.创建XML和临时表结构之间的映射 3. 单次调用做实际加载

【讨论】：