Visual Studio - Sabre GetReservationRS 未在 Intellisense 中显示旅行项目

Question

我正在尝试实施新的 GetReservationRQ/RS API，因为旧的 TravelItineraryReadRQ 显然将于 2018 年 12 月停用。

我能够拨打电话并获得响应，并且所有有效的旅行数据都存在于 XML 有效负载中，但我无法让 Intellisense 显示代理类的 Item 字段中的项目。我可能解释不正确，所以我在下面有一些屏幕截图。

我已尝试深入研究由 WSDL 创建的 reference.cs 文件，并且确实看到 GetReservationRQ 和 TravelItinerarReadRQ 之间创建对象模型的方式存在一些差异，但我不知道该怎么做它。

处于调试模式的填充对象显示所有有效的预留项：

智能感知显示没有任何其他可见成员的项目字段：

编辑 7/26/18

感谢 Carlos 在下面的回答，我通过实施他的更改来完成这项工作。对于后代，这是我的工作代码：

public class GetReservationReq
{

    private GetReservationService service;
    public GetReservationRS response;
    public string xmlResponse;

    public GetReservationReq()
    {
        //parameterless constructor for serializiation
    }

    public GetReservationReq(SessionToken token, string locator)
    {
        //MessageHeader
        MessageHeader mHeader = new MessageHeader();

        PartyId[] pId = { new PartyId() };
        pId[0].Value = "SWS";

        From from = new From();
        from.PartyId = pId;

        To to = new To();
        to.PartyId = pId;

        mHeader.Action = "getReservationRQ";
        mHeader.Service = new Service()
        {
            Value = mHeader.Action
        };
        mHeader.ConversationId = token.conversationID;
        mHeader.CPAId = token.ipcc;
        mHeader.From = from;
        mHeader.To = to;
        mHeader.MessageData = new MessageData()
        {
            Timestamp = DateTime.UtcNow.ToString()
        };

        //Security
        Security sec = new Security();
        //Security1 sec = new Security1();
        sec.BinarySecurityToken = token.securityToken;

        //Service
        service = new GetReservationService();
        service.MessageHeaderValue = mHeader;
        service.SoapVersion = System.Web.Services.Protocols.SoapProtocolVersion.Soap11;
        service.SecurityValue = sec;

        //create the request
        GetReservationRQ req = new GetReservationRQ();
        req.Version = "1.18.0";
        req.RequestType = "Stateful"; //This indicates that we are looking to pull up an existing PNR
        req.Locator = locator;
        req.ReturnOptions = new ReturnOptions();
        req.ReturnOptions.ViewName = "Full";
        req.ReturnOptions.ResponseFormat = "STL";


        try
        {
            //execute the response
            response = service.GetReservationOperation(req);
            //cast response items to usable Object 
            ReservationPNRB content = (ReservationPNRB)response.Item;
            //testing - iterate through reservation elements and do stuff
            foreach (var segment in content.OpenReservationElements.OpenReservationElement)
            {
                Console.WriteLine(segment.id + " - " + segment.type);
            }
            Console.Read();

            //serialize the response for logging if necessary
            xmlResponse = Serializer.toXML(response);


            //serialize response for logging if necessary
            using (StreamWriter myWriter = new StreamWriter(@"C:\SABRE_DATA\TMP\xmlItin.txt", true))
            {
                XmlSerializer mySerializer = new XmlSerializer(typeof(GetReservationRS));
                mySerializer.Serialize(myWriter, response);
                StringWriter myStringWriter = new StringWriter();
                mySerializer.Serialize(myStringWriter, response);
                xmlResponse = myStringWriter.ToString();
            }
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
            throw;
        }
    }
}

Answer 1

正如您在上一个打印屏幕中看到的，Item 属性的类型是 Object。这意味着您需要将其转换为您期望的特定类型。

要找到可以在该属性中返回的有效类型，您需要转到 reference.cs，在那里您将在属性顶部（作为属性）看到 API 可以返回的对象的有效类型在这个属性中。