如何序列化具有 2 个不同列表的 XML 文档？

Question

好的，我正在使用 ASP MVC 并尝试加载一些 XML 数据，在将其转换为 JSON 时需要对其进行序列化。

我不明白的是，我的 XML 有不止一个后代。那么，当我序列化它时，我需要在模型中将每个后代的数据存储在自己的列表中，对吗？

我已经这样做了，所以我有两个单独的列表。那么，如何将这一切序列化到一个 XML 文档中呢？

这是我的 XML 标记示例：

<vehicle>
<make>Suzuki</make>
<color>Yellow></color>
<owner>
    <id>0</id>
    <name>Joe Bloggs</name>
</owner>
<owner>
    <id>1</id>
    <name>Foo Bar</name>
</owner>
</vehicle>

这是我的 XML 模型：

    public partial class vehicle
    {
        private string makeField;
        private string colorField;

        private vehicleOwner[] ownerField;

        /// <remarks/>
        public string make {get; set;}

        /// <remarks/>
        public string color{get; set;}

        [System.Xml.Serialization.XmlElementAttribute("owner")]
        public vehicleOwner[] owner{ get; set;}

        // Keep this in a list to serialize it
        List<vehicle> vehicleList = new List<vehicle>();
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    public partial class vehicleOwner
    {

        private int idField;

        private string nameField;


        /// <remarks/>
        public int id { get; set;}


        /// <remarks/>
        public string nameField {get; set;}


        // Stick it in a list so I can serialize it later
        List<vehicleOwner> vehicleOwnerList = new List<vehicleOwner>();
    }

}

所以，现在我有两个包含 XML 数据的列表：vehicleOwnerList 和 vehicleList。 但这些都是一个 XML 文档。那么我怎样才能为这两个列表序列化呢？我是否必须将它们合并到一个列表中，如果是，我该怎么做？

所以我.E.

 List<vehicleOwner> listCombinedActions = new List<vehicleOwner>();

                XmlDocument xmlDoc = new XmlDocument();
                XPathNavigator nav = xmlDoc.CreateNavigator();
                using (XmlWriter writer = nav.AppendChild())
                {
                    XmlSerializer ser = new XmlSerializer(typeof(List<vehicle>), new XmlRootAttribute("owner"));
                    ser.Serialize(writer, listCombinedActions);
                }

干杯

Answer 1

我希望我了解您想要实现的目标，因此添加示例如何完成：

---

数据模型：

//NOTE: property, root class names is different. 
//So you can name it what you want but you need to specify xml tag name in attribute

[XmlRoot("vehicle")]
public class vehicleObject
{
    public string make { get; set; }
    public string color { get; set; }

    [System.Xml.Serialization.XmlElement("owner")]
    public List<vehicleOwner> ownerList { get; set; }
}

public class vehicleOwner
{
    public int id { get; set; }

    [System.Xml.Serialization.XmlElement("name")]
    public string nameField { get; set; }
} 

---

用法：

vehicleObject yourWorkingObject;

using (MemoryStream ms = new MemoryStream(File.ReadAllBytes("c:\\a.xml")))
{
    XmlSerializer serializer = new XmlSerializer(typeof(vehicleObject));
    yourWorkingObject = serializer.Deserialize(ms) as vehicleObject;
}

//Do with yourWorkingObject here what you want

---

结果：