【发布时间】:2013-04-19 01:05:08
【问题描述】:
这是我的 DateBaseHelper 公共游标 getQuestionsFromQuizID(int quizID){
Integer quiz = Integer.valueOf(quizID);
return myDataBase.rawQuery("select * from Questions where quizID ="+quiz.toString(), null );
}
public Cursor getAnswersFromQuestionID(int questionID, int quizID){
Integer question = Integer.valueOf(questionID);
Integer quiz = Integer.valueOf(quizID);
return myDataBase.rawQuery("select * from Answers where questionID = "+question.toString()+" and quizID = "+quiz.toString(), null );
}
public Boolean isAnswerCorrect(int answerID) {
Integer answer = Integer.valueOf(answerID);
int correctBit;
Cursor cursor = myDataBase.rawQuery("select * from Answers where _id ="
+ answer.toString(), null);
cursor.moveToFirst();
correctBit = cursor.getInt(3);
if (correctBit == 1) {
return true;
} else {
return false;
}
}
public int getQuestionCountByQuizID(int quizID){
Integer quiz = Integer.valueOf(quizID);
Cursor cursor = myDataBase.rawQuery("select * from Questions where quizID ="+quiz.toString(), null);
cursor.moveToFirst();
return cursor.getCount();
}
...我有测验活动的方法
私人无效getNextQuestion(){ 字符串问题;
// set question count text at the top of screen using string
// concatenation
Integer currentCount = new Integer(curQuestion + 1);
((TextView) findViewById(R.id.questioncount)).setText("Question "
+ currentCount.toString() + " of "
+ totalQuestionCount.toString());
// get quizID based on which button was pressed on PickQuizActivity
int quizID = getIntent().getExtras().getInt("quizID");
// use returned cursor to get question as string
Cursor questionCursor = myDbHelper.getQuestionsFromQuizID(quizID);
questionCursor.moveToPosition(curQuestion);
// getString(3): gets the zero-indexed column 2 from current row cursor
// is on
question = questionCursor.getString(2);
// update UI to show question pulled from database
((TextView) findViewById(R.id.question)).setText(question);
Cursor answerCursor = myDbHelper.getAnswersFromQuestionID(
curQuestion + 1, quizID);
// set each answer text, there will always be 4 answers
// also collect questionID for isCorrect check when onClick is called
answerCursor.moveToFirst();
((TextView) findViewById(R.id.answer1)).setText(answerCursor
.getString(4));
answerID1 = answerCursor.getInt(0);
answerCursor.moveToNext();
((TextView) findViewById(R.id.answer2)).setText(answerCursor
.getString(4));
answerID2 = answerCursor.getInt(0);
answerCursor.moveToNext();
((TextView) findViewById(R.id.answer3)).setText(answerCursor
.getString(4));
answerID3 = answerCursor.getInt(0);
answerCursor.moveToNext();
((TextView) findViewById(R.id.answer4)).setText(answerCursor
.getString(4));
answerID4 = answerCursor.getInt(0);
// increment question counter, will be used to retrieve next question
curQuestion++;
// set flag for last question reached
if (questionCursor.isLast()) {
lastQuestionReached = true;
}
}
所以...当我不显示随机问题时,我编辑 sql,只需添加 SORT BY RANDOM() LIMIT 10 我的问题和答案混淆了......
任何人都可以知道如何在不重复的情况下获得随机问题的解决方案吗? 以及如何避免问题和答案的混合数据?
【问题讨论】: