【发布时间】:2011-12-12 18:59:48
【问题描述】:
我想在 Windows 窗体中编辑我的 datagridview,然后单击更新到数据库的“保存”按钮。
public void button1_Click(object sender, EventArgs e)
{
string txt = textBox1.Text;
string strOleDbConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\\Project.mdb";
string strSqlStatement = string.Empty;
strSqlStatement = "SELECT * FROM jiahe WHERE [User] = '" + txt + "'";
OleDbConnection objConnection = new OleDbConnection(strOleDbConnectionString);
OleDbDataAdapter objAdapter = new OleDbDataAdapter(strSqlStatement, objConnection);
DataSet ds = new DataSet();
objAdapter.Fill(ds);
DataTable dt = ds.Tables[0];
dataGridView1.DataSource = dt.DefaultView;
try
{
if (dt.Rows.Count == 1)
{
string strLine = string.Empty;
string strUser = string.Empty;
foreach (DataRow dr in dt.Rows)
{
string strTags = dr["Tag ID"].ToString();
strUser = dr["User"].ToString();
string strAge = dr["Age"].ToString();
string strPhoneNumber = dr["Phone Number"].ToString();
DataTable dataTable = new DataTable();
string updateString = @"update jiahe set Age = ' " + strAge + " ' where [User] = '" + textBox1.Text + "'";
OleDbCommand cmd1 = new OleDbCommand(updateString, objConnection);
cmd1.Connection.Open();
string str = cmd1.ExecuteNonQuery().ToString();
cmd1.Connection.Close();
}
}
else
{
if (dt.Rows.Count == 0)
{
MessageBox.Show("Invalid input!");
}
}
}
catch (Exception)
{
MessageBox.Show("Error!");
}
}
我的“保存”按钮:
private void button2_Click(object sender, EventArgs e)
{
try
{
objAdapter.Update(dt);
}
catch (Exception exx)
{
MessageBox.Show(exx.ToString());
}
}
当我单击保存时,在 objAdapter.Update(dt); 处出现“未设置对象引用..”错误。请告诉我我在这里缺少什么。我正在自学 c#,而且还很新,所以不要对我苛刻。
【问题讨论】:
-
这里有一个提示:我敢打赌这不一样
objAdapter。一个是类成员,另一个是局部变量。