【问题标题】：Speech recognition for Python 3.4 thats easy to work?Python 3.4 的语音识别好用吗？
【发布时间】：2015-11-26 09:32:10
【问题描述】：

我希望获得一个简单有效的语音识别。我一直在speech_recognition上看这个，当我执行代码时出现以下错误

import speech_recognition as sr
r = sr.Recognizer()
with sr.Microphone() as source:                
    audio = r.listen(source)                  

try:
    print("You said " + r.recognize(audio))    
except LookupError:                            




print("You said " + r.recognize(audio))    # recognize speech using Google       Speech Recognition
AttributeError: 'Recognizer' object has no attribute 'recognize'

    print("Could not understand audio")

这是从他们网页上的示例中复制的

【问题讨论】：

标签： python python-3.x speech-recognition google-speech-api

【解决方案1】：

我也遇到了同样的问题。问题是我没有设置最低阈值水平。所以我添加了这段代码。

import speech_recognition as sr
r = sr.Recognizer()
m = sr.Microphone()
#set threhold level
with m as source: r.adjust_for_ambient_noise(source)
print("Set minimum energy threshold to {}".format(r.energy_threshold))
# obtain audio from the microphone

with sr.Microphone() as source:
    print("Say something!")
    audio = r.listen(source)

print(r.recognize_google(audio))

现在完美运行！！！

【讨论】：

【解决方案2】：

我让它工作了。

import speech_recognition as sr

# obtain audio from the microphone
r = sr.Recognizer()
with sr.Microphone() as source:
    print("Say something!")
    audio = r.listen(source)

print(r.recognize_google(audio))

【讨论】：

【解决方案3】：

您使用什么版本的 SpeechRecognition 库？

您可以通过以下方式进行检查：

import speech_recognition as sr
print sr.__version__

如果您使用的是最新版本 (SpeechRecognition 3.1.3)，则应使用 recognize_google() 方法而不是 recognize()，以使用 Google API。

至于最新的文档，你可以查一下here，还有一些有用的examples。

【讨论】：

【解决方案4】：

我获取了一个实际执行但无法打印出我说的话的代码

注意：此示例需要 PyAudio，因为它使用 Microphone 类

import speech_recognition as sr
import pyaudio

# obtain audio from the microphone
r = sr.Recognizer()
with sr.Microphone() as source:
    print("Say something!")
    audio = r.listen(source)

# recognize speech using Google Speech Recognition
try:
    # for testing purposes, we're just using the default API key
    # to use another API key, use `r.recognize_google(audio, key="GOOGLE_SPEECH_RECOGNITION_API_KEY")`
    # instead of `r.recognize_google(audio)`
    print("Google Speech Recognition thinks you said " + r.recognize_google(audio))
except sr.UnknownValueError:
    print("Google Speech Recognition could not understand audio")
except sr.RequestError as e:
    print("Could not request results from Google Speech Recognition service; {0}".format(e))

# recognize speech using Wit.ai
WIT_AI_KEY = "INSERT WIT.AI API KEY HERE" # Wit.ai keys are 32-character uppercase alphanumeric strings
try:
    print("Wit.ai thinks you said " + r.recognize_wit(audio, key=WIT_AI_KEY))
except sr.UnknownValueError:
    print("Wit.ai could not understand audio")
except sr.RequestError as e:
    print("Could not request results from Wit.ai service; {0}".format(e))

# recognize speech using IBM Speech to Text
IBM_USERNAME = "INSERT IBM SPEECH TO TEXT USERNAME HERE" # IBM Speech to Text usernames are strings of the form XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX
IBM_PASSWORD = "INSERT IBM SPEECH TO TEXT PASSWORD HERE" # IBM Speech to Text passwords are mixed-case alphanumeric strings
try:
    print("IBM Speech to Text thinks you said " + r.recognize_ibm(audio, username=IBM_USERNAME, password=IBM_PASSWORD))
except sr.UnknownValueError:
    print("IBM Speech to Text could not understand audio")
except sr.RequestError as e:
    print("Could not request results from IBM Speech to Text service; {0}".format(e))

# recognize speech using AT&T Speech to Text
ATT_APP_KEY = "INSERT AT&T SPEECH TO TEXT APP KEY HERE" # AT&T Speech to Text app keys are 32-character lowercase alphanumeric strings
ATT_APP_SECRET = "INSERT AT&T SPEECH TO TEXT APP SECRET HERE" # AT&T Speech to Text app secrets are 32-character lowercase alphanumeric strings
try:
    print("AT&T Speech to Text thinks you said " + r.recognize_att(audio, app_key=ATT_APP_KEY, app_secret=ATT_APP_SECRET))
except sr.UnknownValueError:
    print("AT&T Speech to Text could not understand audio")
except sr.RequestError as e:
    print("Could not request results from AT&T Speech to Text service; {0}".format(e))

我读到以下内容

说点什么！谷歌语音识别认为你打招呼无法从 Wit.ai 服务请求结果；识别请求失败：错误请求无法从 IBM Speech to Text 服务请求结果；识别请求失败：未经授权无法从 AT&T Speech to Text 服务请求结果；凭据请求失败：未经授权

【讨论】：