【发布时间】:2021-09-09 12:34:17
【问题描述】:
拥有这个实体:
User.java:
@Entity
@Data
@NoArgsConstructor
public class User {
@Id @GeneratedValue
private int id;
private String username;
private String about;
@OneToMany(mappedBy = "owner", cascade = CascadeType.ALL, orphanRemoval = true, fetch = FetchType.EAGER)
private Map<User, Friendship> friendships = new HashMap<>();
@OneToMany(mappedBy = "author", cascade = CascadeType.ALL, orphanRemoval = true, fetch = FetchType.EAGER)
private Collection<Post> posts = new ArrayList<>();
public User(String username) {
this.username = username;
}
public void addFriend(User friend){
Friendship friendship = new Friendship();
friendship.setOwner(this);
friendship.setFriend(friend);
this.friendships.put(friend, friendship);
}
public void addPost(Post post){
post.setAuthor(this);
this.posts.add(post);
}
}
Friendship.java:
@Entity
@Getter
@Setter
@NoArgsConstructor
public class Friendship {
@EmbeddedId
private FriendshipId key = new FriendshipId();
private String level;
@ManyToOne
@MapsId("ownerId")
private User owner;
@ManyToOne
@MapsId("friendId")
private User friend;
}
FriendshipId.java:
@Embeddable
public class FriendshipId implements Serializable {
private int ownerId;
private int friendId;
}
UserRepository.java:
public interface UserRepository extends JpaRepository<User, Integer> {
public User findByUsername(String username);
}
最后DemoApplication.java:
@Bean
public CommandLineRunner dataLoader(UserRepository userRepo, FriendshipRepository friendshipRepo){
return new CommandLineRunner() {
@Override
public void run(String... args) throws Exception {
User f1 = new User("friend1");
User f2 = new User("friend2");
User u1 = new User("user1");
u1.addFriend(f1);
u1.addFriend(f2);
userRepo.save(u1);
User fetchedUser = userRepo.findByUsername("user1");
System.out.println(fetchedUser);
System.out.println(fetchedUser.getFriendships().get(f1));
}
};
}
userRepo.save(u1)操作后的表格如下:
mysql> select * from user;
+----+-------+----------+
| id | about | username |
+----+-------+----------+
| 1 | NULL | user1 |
| 2 | NULL | friend1 |
| 3 | NULL | friend2 |
+----+-------+----------+
select * from friendship;
+-------+-----------+----------+-----------------+
| level | friend_id | owner_id | friendships_key |
+-------+-----------+----------+-----------------+
| NULL | 2 | 1 | 2 |
| NULL | 3 | 1 | 3 |
+-------+-----------+----------+-----------------+
如您所见,所有朋友都已保存。然而这句话:
System.out.println(fetchedUser.getFriendships().get(f1));
返回null。即使fetchedUser 获取了朋友地图:
System.out.println(fetchedUser);
打印:
User(id=1, username=user1, about=null, friendships={User(id=2, username=friend1, about=null, friendships={}, posts=[])=com.example.demo.model.Friendship@152581e8, User(id=3, username=friend2, about=null, friendships={}, posts=[])=com.example.demo.model.Friendship@58a5d38}, posts=[])
那么,当地图friendships 被完全提取(所有朋友都被提取,从上面的语句中可以看出)时,为什么无法提取朋友f1(更确切地说是null)?
PS:
我已经删除了@Data lombok 注释(只是添加了@Getter、@Setter 和@NoArgsConstrutor`)并自己覆盖了equalsAndHashCode:
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (!(o instanceof User)) return false;
User user = (User) o;
return id == user.id && Objects.equals(username, user.username) && Objects.equals(about, user.about) && Objects.equals(friendships, user.friendships) && Objects.equals(posts, user.posts);
}
@Override
public int hashCode() {
return Objects.hash(id, username, about, friendships, posts);
}
或者换句话说,equals() 方法使用了User 类的所有字段。
【问题讨论】:
-
我认为您缺少 EqualsAndHashcode 实现。
-
@SKumar 用户有
@Datalombok 注释,它应该覆盖 EqualAndHascode。 -
好的,但它是否知道在
User类的所有字段中,它只需要在username字段上进行验证?id也已填充。您能否确认,如果您登录f1,它已填充了id。我怀疑它没有。 -
@SKumar 我不明白你的意思,但如果你看一下编辑,我自己已经覆盖了 equals 和 hashCode(IDE 确实做到了)
-
@SKumar 被覆盖的
equals()现在正在使用所有字段
标签: java spring hibernate crud