Play (Scala) 类型安全配置中的 *Ordered* 对象答案

【问题标题】：*Ordered* objects in Play (Scala) typesafe configPlay (Scala) 类型安全配置中的 *Ordered* 对象
【发布时间】：2018-07-20 19:38:46
【问题描述】：

如何在 Play 2.6.x (Scala) 的以下 .conf 中访问customers 的有序列表：

customers {
  "cust1" {
    env1 {
      att1: "str1"
      att2: "str2"
    }
    env2 {
      att1: "str3"
      att2: "str5"
    }
    env3 {
      att1: "str2"
      att2: "str6"
    }
    env4 {
      att1: "str1"
      att2: "str2"
    }
  }
  "cust2" {
    env1 {
      att1: "faldfjalfj"
      att2: "reqwrewrqrq"
    }
    env2 {
      att1: "falalfj"
      att2: "reqwrrq"
    }
  }
  "cust3" {
    env3 {
      att1: "xvcbzxbv"
      att2: "hello"
    }
  }
}

List("cust1", "cust2", "cust3")，在这个例子中。

【问题讨论】：

标签： scala playframework typesafe-config

【解决方案1】：

下面的例子应该可以工作：

val config : Configuration = ???
config.getObject("customers").entrySet().asScala.map(_.getKey).toList

编辑

如果客户按字典顺序排列，您可以致电.sorted

如果更改您的配置不会影响您已经实现的逻辑，那么您可以像这样重构您的配置：

customers : [
  {
    name : "cust1"
    env1 {
      att1: "str1"
      att2: "str2"
    }
    env2 {
      att1: "str3"
      att2: "str5"
    }
    env3 {
      att1: "str2"
      att2: "str6"
    }
    env4 {
      att1: "str1"
      att2: "str2"
    }
  }
   {
    name : "cust2"
    env1 {
      att1: "faldfjalfj"
      att2: "reqwrewrqrq"
    }
    env2 {
      att1: "falalfj"
      att2: "reqwrrq"
    }
  }
  {
    name: "cust3"
    env3 {
      att1: "xvcbzxbv"
      att2: "hello"
    }
  }
  {
    name : "bob"
    env1 {
      att1: "str1"
      att2: "str2"
    }
    env2 {
      att1: "str3"
      att2: "str5"
    }
    env3 {
      att1: "str2"
      att2: "str6"
    }
    env4 {
      att1: "str1"
      att2: "str2"
    }
  }
  {
    name : "john"
    env1 {
      att1: "faldfjalfj"
      att2: "reqwrewrqrq"
    }
    env2 {
      att1: "falalfj"
      att2: "reqwrrq"
    }
  }
  {
    name: "jack"
    env3 {
      att1: "xvcbzxbv"
      att2: "hello"
    }
  }
]

使用pureconfig，您可以执行以下操作：

import pureconfig.loadConfigOrThrow

final case class Named(name: String)

loadConfigOrThrow[List[Named]]("customers").map(_.name)

【讨论】：

【解决方案2】：

class SomeClass @Inject()(config: Configuration) {
  Logger.debug("Customers from config: " + config.underlying.getConfig("customers"))
}

会给你的。

Customers from config: Config(SimpleConfigObject(
    {"cust1":{
        "env1":{"att1":"str1","att2":"str2"},
        "env2":{"att1":"str3","att2":"str5"},
        "env3":{"att1":"str2","att2":"str6"},
        "env4":{"att1":"str1","att2":"str2"}},
    "cust2":{
        "env1":{"att1":"faldfjalfj","att2":"reqwrewrqrq"},
        "env2":{"att1":"falalfj","att2":"reqwrrq"}},
   "cust3":{
        "env3":{"att1":"xvcbzxbv","att2":"hello"}}}))

如果您想使用对象，显然必须对其进行转换。

【讨论】：