【发布时间】：2020-02-25 16:47:14
【问题描述】：
情况描述：我在远程计算机 B 上运行了一个 Ubuntu VM。我可以通过在我的主机（计算机 A）上执行的 SSH 访问这台计算机 B。 当我在计算机 B 上通过 SSH 进入交互式 shell 时，我可以毫无问题地执行所有 docker 命令，步骤如下：
-
ssh user@remote_IP（在远程 shell 中交互输入） -
docker-compose run -d --name wfirst --user 1000:1000 container（编写一个 docker 容器并启动它）
这非常有效，我的容器已安装、启动并运行。 但是，如果我尝试通过在主机终端中写入以非交互方式运行该命令：
ssh user@remoteIP "cd /path_to_docker_file;docker-compose run -d --name wfirst --user 1000:1000 container"
命令不成功，我的容器没有挂载，没有运行。通过使用 docker-compose 命令上的"--verbose" 标志，我能够获得更多信息。
这里是成功方法输出的有趣部分：
compose.config.config.find: Using configuration files: ./docker-compose.yml
WARNING: compose.config.environment.__getitem__: The DISPLAY variable is not set. Defaulting to a blank string.
WARNING: compose.config.environment.__getitem__: The NO_PROXY variable is not set. Defaulting to a blank string.
docker.utils.config.find_config_file: Trying paths: ['/home/user/.docker/config.json', '/home/user/.dockercfg']
docker.utils.config.find_config_file: No config file found
docker.utils.config.find_config_file: Trying paths: ['/home/user/.docker/config.json', '/home/user/.dockercfg']
docker.utils.config.find_config_file: No config file found
urllib3.connectionpool._new_conn: Starting new HTTP connection (1): localhost:2375
urllib3.connectionpool._make_request: http://localhost:2375 "GET /v1.25/version HTTP/1.1" 200 758
compose.cli.command.get_client: docker-compose version 1.21.0, build unknown
docker-py version: 3.4.1
CPython version: 3.7.5
OpenSSL version: OpenSSL 1.1.1c 28 May 2019
compose.cli.command.get_client: Docker base_url: http://localhost:2375
...
我们可以看到与 docker 的 HTTP 连接已成功建立。然后该命令继续执行并能够从 docker 映像创建容器。
这里是失败方法的输出：
compose.config.config.find: Using configuration files: ./docker-compose.yml
compose.config.environment.__getitem__: The DISPLAY variable is not set. Defaulting to a blank string.
compose.config.environment.__getitem__: The NO_PROXY variable is not set. Defaulting to a blank string.
docker.utils.config.find_config_file: Trying paths: ['/home/user/.docker/config.json', '/home/user/.dockercfg']
docker.utils.config.find_config_file: No config file found
docker.utils.config.find_config_file: Trying paths: ['/home/user/.docker/config.json', '/home/user/.dockercfg']
docker.utils.config.find_config_file: No config file found
Traceback (most recent call last):
File "/usr/lib/python3/dist-packages/urllib3/connectionpool.py", line 384, in _make_request
six.raise_from(e, None)
File "<string>", line 3, in raise_from
File "/usr/lib/python3/dist-packages/urllib3/connectionpool.py", line 380, in _make_request
httplib_response = conn.getresponse()
File "/usr/lib/python3.7/http/client.py", line 1344, in getresponse
response.begin()
File "/usr/lib/python3.7/http/client.py", line 306, in begin
version, status, reason = self._read_status()
File "/usr/lib/python3.7/http/client.py", line 267, in _read_status
line = str(self.fp.readline(_MAXLINE + 1), "iso-8859-1")
File "/usr/lib/python3.7/socket.py", line 589, in readinto
return self._sock.recv_into(b)
socket.timeout: timed out
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/usr/lib/python3/dist-packages/requests/adapters.py", line 449, in send
timeout=timeout
File "/usr/lib/python3/dist-packages/urllib3/connectionpool.py", line 638, in urlopen
_stacktrace=sys.exc_info()[2])
File "/usr/lib/python3/dist-packages/urllib3/util/retry.py", line 367, in increment
raise six.reraise(type(error), error, _stacktrace)
File "/usr/lib/python3/dist-packages/six.py", line 693, in reraise
raise value
File "/usr/lib/python3/dist-packages/urllib3/connectionpool.py", line 600, in urlopen
chunked=chunked)
File "/usr/lib/python3/dist-packages/urllib3/connectionpool.py", line 386, in _make_request
self._raise_timeout(err=e, url=url, timeout_value=read_timeout)
File "/usr/lib/python3/dist-packages/urllib3/connectionpool.py", line 306, in _raise_timeout
raise ReadTimeoutError(self, url, "Read timed out. (read timeout=%s)" % timeout_value)
urllib3.exceptions.ReadTimeoutError: UnixHTTPConnectionPool(host='localhost', port=None): Read timed out. (read timeout=60)
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/usr/bin/docker-compose", line 11, in <module>
load_entry_point('docker-compose==1.21.0', 'console_scripts', 'docker-compose')()
File "/usr/lib/python3/dist-packages/compose/cli/main.py", line 71, in main
command()
File "/usr/lib/python3/dist-packages/compose/cli/main.py", line 124, in perform_command
project = project_from_options('.', options)
File "/usr/lib/python3/dist-packages/compose/cli/command.py", line 41, in project_from_options
compatibility=options.get('--compatibility'),
File "/usr/lib/python3/dist-packages/compose/cli/command.py", line 121, in get_project
host=host, environment=environment
File "/usr/lib/python3/dist-packages/compose/cli/command.py", line 95, in get_client
version_info = six.iteritems(client.version())
File "/usr/lib/python3/dist-packages/docker/api/daemon.py", line 181, in version
return self._result(self._get(url), json=True)
File "/usr/lib/python3/dist-packages/docker/utils/decorators.py", line 46, in inner
return f(self, *args, **kwargs)
File "/usr/lib/python3/dist-packages/docker/api/client.py", line 198, in _get
return self.get(url, **self._set_request_timeout(kwargs))
File "/usr/lib/python3/dist-packages/requests/sessions.py", line 546, in get
return self.request('GET', url, **kwargs)
File "/usr/lib/python3/dist-packages/requests/sessions.py", line 533, in request
resp = self.send(prep, **send_kwargs)
File "/usr/lib/python3/dist-packages/requests/sessions.py", line 646, in send
r = adapter.send(request, **kwargs)
File "/usr/lib/python3/dist-packages/requests/adapters.py", line 529, in send
raise ReadTimeout(e, request=request)
requests.exceptions.ReadTimeout: UnixHTTPConnectionPool(host='localhost', port=None): Read timed out. (read timeout=60)
我们可以看到HTTP连接无法建立。
为什么我需要以非交互方式发送命令？最初，我想使用 Jenkins 发送这些命令（我在 Jenkins 中添加了一个 SSH 插件），我注意到 docker 命令不起作用（与本文中显示的输出相同）。经过几次测试，我意识到当 Jenkins 使用 SSH 时，他以非交互方式发送命令：
- ssh user@remote_IP "commands_to_execute"
这种非交互式方式对于简单命令来说不是问题，但对于一些需要在交互式 shell 中执行的 docker 命令来说似乎是一个问题，我猜？ 是否有人找到了在非交互式 shell 中成功执行 docker 命令的解决方法？任何帮助、提示或替代解决方案都将不胜感激，因为到目前为止我尝试了很多事情但没有成功..
【问题讨论】：