【发布时间】:2022-01-16 22:06:06
【问题描述】:
我有四张桌子:
- 页面
- wikiPageID
- 网址
- 收藏
- collectionID
- wikiPageID
- PageReference(连接表)
- wikiPageID
- 参考ID
- 参考
- 参考ID
对于与page 表中的行对应的任何给定 URL,我想返回分配给可能属于同一集合的任何同级页面的所有引用。
我觉得可能有更有效的方法来做到这一点。到目前为止,我已将其分解为一组查询,并且只完成了一半。
# Get all ReferenceData from Reference table for ID
wikiPageID = ""
url = request.json['url']
# Get WikiPageID from Page table where Page.url = request.json['url']
for item in db.session.query(PageModel).filter(PageModel.url == url).values('wikiPageID'):
wikiPageID = item[0]
#print(wikiPageID)
for item in
db.session.query(CollectionModel).filter(CollectionModel.wikiPageID == wikiPageID).values('collectionID'):
collectionID = item[0]
#print(collectionID)
# Get all WikiPageID's from Collection table where WikiPageID EXISTS
result1 = db.session.query(CollectionModel).filter(CollectionModel.collectionID == collectionID).values('wikiPageID')
## THIS IS WHERE IT STARTS GOING PEAR SHAPED
# Get all ReferenceID from PageReference where WikiPageID EXISTS
result = db.session.query(PageReferenceModel).filter(PageReferenceModel.wikiPageID.in_(result1) )
schema = CollectionSchema()
return schema.dump(result, many=True), 200
在我的最后一个查询中,我试图嵌套之前的查询结果。当我试图通过从先前结果传递的 ID 过滤结果时。我觉得我做错了,不知道从哪里开始。
SQLAlchemy 模型
class CollectionModel(db.Model):
__tablename__ = "Collection"
collectionID = db.Column(db.Integer, primary_key=True)
wikiPageID = db.Column(db.Integer, db.ForeignKey('Page.wikiPageID'), nullable=False)
Page = db.relationship("PageModel")
class PageModel(db.Model):
__tablename__ = "Page"
wikiPageID = db.Column(db.Integer, primary_key=True)
langCode = db.Column(db.String, nullable=True)
title = db.Column(db.String, nullable=True)
url = db.Column(db.String, nullable=True)
summary = db.Column(db.String, nullable=True)
lastUpdated = db.Column(db.String, nullable=True)
class PageReferenceModel(db.Model):
__tablename__ = "PageReference"
pageReferenceID = db.Column(db.Integer, primary_key=True)
wikiPageID = db.Column(db.Integer, db.ForeignKey('Page.wikiPageID'), nullable=False)
referenceID = db.Column(db.Integer, db.ForeignKey('Reference.referenceID'), nullable=False)
Page = db.relationship("PageModel")
Reference = db.relationship("ReferenceModel")
class ReferenceModel(db.Model):
__tablename__ = "Reference"
referenceID = db.Column(db.Integer, primary_key=True)
langCode = db.Column(db.String, nullable=False)
isGov = db.Column(db.String, nullable=False)
type = db.Column(db.String, nullable=True)
title = db.Column(db.String, nullable=True)
domain = db.Column(db.String, nullable=True)
suffix = db.Column(db.String, nullable=True)
description = db.Column(db.String, nullable=True)
publishDate = db.Column(db.String, nullable=True)
url = db.Column(db.String, nullable=True)
youtubeId = db.Column(db.String, nullable=True)
langCheck = db.Column(db.Boolean, nullable=True)
【问题讨论】:
标签: flask sqlalchemy