如何使用 Spring Data CouchBase 'findAll(Iterable<ID>)' 方法？答案

【问题标题】：How to use Spring Data CouchBase 'findAll(Iterable<ID>)' Method?如何使用 Spring Data CouchBase 'findAll(Iterable<ID>)' 方法？
【发布时间】：2014-06-03 12:34:34
【问题描述】：

我正在尝试使用 Spring-Data-Couchbase。

我想从 findAll(Iterable) 方法中获取 List。我将视图“全部”设置为我的生产视图。

但是，我遇到了例外。如何使用 findAll(Iterable) 方法？

以下是示例代码和异常。

文档类：

@Document
public class User {
    @Id
    private String id;
    private String userSeq;
}

存储库类：

public interface UserRepository extends CouchbaseRepository<User, String> {
}

服务类：

//List<String> get the Same result & exception.
Set<String> friendSet = new HashSet<String>();
friendSet.add("User8");
friendSet.add("User6");

userRepository.findAll(friendSet)

例外：

Caused by: java.util.concurrent.ExecutionException: OperationException: SERVER: bad_request Reason: invalid UTF-8 JSON: {{error,{2,"lexical error: invalid char in json text.\n"}},
                 "[User8, User6]"}
at com.couchbase.client.internal.HttpFuture.waitForAndCheckOperation(HttpFuture.java:98)
at com.couchbase.client.internal.HttpFuture.get(HttpFuture.java:82)
at com.couchbase.client.internal.HttpFuture.get(HttpFuture.java:72)
at com.couchbase.client.CouchbaseClient.query(CouchbaseClient.java:778)
... 66 more
Caused by: OperationException: SERVER: bad_request Reason: invalid UTF-8 JSON: {{error,{2,"lexical error: invalid char in json text.\n"}},
                 "[User8, User6]"}
at com.couchbase.client.protocol.views.NoDocsOperationImpl.parseError(NoDocsOperationImpl.java:110)
at com.couchbase.client.protocol.views.ViewOperationImpl.handleResponse(ViewOperationImpl.java:68)
at com.couchbase.client.http.HttpResponseCallback.completed(HttpResponseCallback.java:103)
at com.couchbase.client.http.HttpResponseCallback.completed(HttpResponseCallback.java:51)
at org.apache.http.concurrent.BasicFuture.completed(BasicFuture.java:115)
at org.apache.http.nio.protocol.HttpAsyncRequester$RequestExecutionCallback.completed(HttpAsyncRequester.java:376)
at org.apache.http.concurrent.BasicFuture.completed(BasicFuture.java:115)
at org.apache.http.nio.protocol.BasicAsyncClientExchangeHandler.responseCompleted(BasicAsyncClientExchangeHandler.java:179)
at org.apache.http.nio.protocol.HttpAsyncRequestExecutor.processResponse(HttpAsyncRequestExecutor.java:349)
at org.apache.http.nio.protocol.HttpAsyncRequestExecutor.inputReady(HttpAsyncRequestExecutor.java:236)
at org.apache.http.impl.nio.DefaultNHttpClientConnection.consumeInput(DefaultNHttpClientConnection.java:267)
at org.apache.http.impl.nio.DefaultHttpClientIODispatch.onInputReady(DefaultHttpClientIODispatch.java:165)
at org.apache.http.impl.nio.DefaultHttpClientIODispatch.onInputReady(DefaultHttpClientIODispatch.java:51)
at org.apache.http.impl.nio.reactor.AbstractIODispatch.inputReady(AbstractIODispatch.java:113)
at org.apache.http.impl.nio.reactor.BaseIOReactor.readable(BaseIOReactor.java:159)
at org.apache.http.impl.nio.reactor.AbstractIOReactor.processEvent(AbstractIOReactor.java:338)
at org.apache.http.impl.nio.reactor.AbstractIOReactor.processEvents(AbstractIOReactor.java:316)
at org.apache.http.impl.nio.reactor.AbstractIOReactor.execute(AbstractIOReactor.java:277)
at org.apache.http.impl.nio.reactor.BaseIOReactor.execute(BaseIOReactor.java:105)
at org.apache.http.impl.nio.reactor.AbstractMultiworkerIOReactor$Worker.run(AbstractMultiworkerIOReactor.java:584)
... 1 more

【问题讨论】：

标签： couchbase spring-data-couchbase

【解决方案1】：

你必须在调用findAll(...)之前引用id:s。

    Set<String> friendSet = new HashSet<String>();
    friendSet.add("\"User8\"");
    friendSet.add("\"User6\"");

如果没有引用 id:s，则发送到 Couchbase 服务器的 keys 参数将类似于 [User8, User6] ，它不是有效的 JSON，因此会出现异常。非常令人惊讶的行为......

【讨论】：