我有一个数组。该数组可以包含 1 到 7 个唯一的日期名称字符串。日期名称将按从周一到周日的顺序排列。 - 例如：
[“周二”、“周四”、“周日”]
我想使用 javascript 对该数组进行排序，以便从今天开始排序。
ie：如果今天是星期五，那么排序后的数组应该是
[“星期日”、“星期二”、“星期四”]
如果今天是星期四，那么排序后的数组应该是
[“周四”、“周日”、“周二”]
谁能帮忙？
【问题讨论】：
标签： javascript algorithm function sorting
function sort_days(days) {
要获取今天的星期几，请使用new Date().getDay()。这假设Sunday = 0, Monday = 1, ..., Saturday = 6。
var day_of_week = new Date().getDay();
要生成星期几的列表，然后对名称列表进行切片：
var list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
var sorted_list = list.slice(day_of_week).concat(list.slice(0,day_of_week));
（今天是星期五，所以sorted_list 是['Fri','Sat','Sun','Mon','Tue','Wed','Thu']）
最后，排序，使用indexOf:
return days.sort(function(a,b) { return sorted_list.indexOf(a) > sorted_list.indexOf(b); });
}
把它们放在一起：
function sort_days(days) {
var day_of_week = new Date().getDay();
var list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
var sorted_list = list.slice(day_of_week).concat(list.slice(0,day_of_week));
return days.sort(function(a,b) { return sorted_list.indexOf(a) > sorted_list.indexOf(b); });
}
【讨论】：
dayName 成员 viariable 对对象进行排序，这是一周中的一天。我所要做的就是将最后一行更改为return sorted_list.indexOf(a.dayName) > sorted_list.indexOf(b.dayName)
const days = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"];
const sortDays = function (a, b) {
a = days.indexOf(a);
b = days.indexOf(b);
return a < b ? 0 : 1;
};
const myArrayOfDays = ["Tuesday", "Saturday", "Monday", "Thursday"].sort(sortDays);
// returns ["Monday", "Tuesday", "Thursday", "Saturday"];
【讨论】：
这是我想出的一个函数：
function sortDays(days) {
var daysOfWeek = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
var today = new Date().getDay();
for (var i=0;i<today;i++) daysOfWeek.push(daysOfWeek.shift());
return daysOfWeek.filter(function(d) { return days.indexOf(d) >= 0; });
}
总体思路是通过根据今天是哪一天从头到尾旋转元素来重新安排一周中的日子。然后，您使用该排序来重新排序您的输入数组以匹配。我没有实际排序，而是根据输入数组的内容过滤了daysOfWeek 数组。
我不确定Array.filter 的支持情况如何，因此您可能希望将其更改为通用 for 循环，而不是取决于您想要支持的浏览器。
Here's a jsfiddle 你也可以在这里玩。
或者，您可以按照类似的策略使用内置的Array.sort 方法：
var daysOfWeek = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
{
var today = new Date().getDay();
for (var i=0;i<today;i++) daysOfWeek.push(daysOfWeek.shift());
}
function daysOfWeekSorter(x,y) {
return daysOfWeek.indexOf(x)-daysOfWeek.indexOf(y);
}
var myDays = ["Tue", "Thu", "Sun"];
myDays.sort(daysOfWeekSorter);
还有here's another fiddle 一起玩。
【讨论】：
以防万一我们设法获得或失去一天，我已经建立了我的不需要硬编码的日期列表 :) 希望有一天我们能在周六和周日之间获得额外的 24 小时！
function anyDayNow( dys ) {
var ret = [], cur = new Date(), today = cur.getUTCDay(), txt;
do {
txt = cur.toUTCString().split(',')[0];
dys.indexOf(txt)!=-1 && ret.push(txt);
cur.setUTCDate( cur.getUTCDate() + 1 );
} while ( cur.getUTCDay() != today );
return ret;
}
console.log( anyDayNow( ["Tue", "Thu", "Sun"] ) );
【讨论】：
这里有一个简单的方法，只使用数组的indexOf、splice filter和concat函数，不需要循环：
function sortMyArray(toSort) {
var today = new Date().toUTCString().substr(0, 3), //get today as 3 letter string
list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"], // days list
before = list.splice(0, list.indexOf(today)); // splice what is before today in the list
list = list.concat(before); // concat the list with what was spliced
return list.filter(function (item) { return toSort.indexOf(item) !== -1}); // return the sorted list with only the asked days
}
使用
console.log(sortMyArray(["Tue", "Thu", "Sun"]));
【讨论】：
这是一种解决问题的有趣方法 - 如果这也相当高效（即没有复杂的对象等），也不会感到惊讶
const sortDays = days => {
let arr = ['', '', '', '', '', '', '']
days.forEach(day => {
if (day === 'Sun') arr[0] = 'Sun'
if (day === 'Mon') arr[1] = 'Mon'
if (day === 'Tue') arr[2] = 'Tue'
if (day === 'Wed') arr[3] = 'Wed'
if (day === 'Thu') arr[4] = 'Thu'
if (day === 'Fri') arr[5] = 'Fri'
if (day === 'Sat') arr[6] = 'Sat'
})
return arr.filter(str => str !== '')
}
【讨论】：
我还选择了filter 选项。
const inOrderDays = arr => {
const list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
return list.filter(each => arr.includes(each));
}
【讨论】：
function sortDaysByToday(ds){
var days = {Sun: 0, Mon: 1, Tue: 2, Wed: 3, Thu: 4, Fri: 5, Sat: 6},
today = new Date().getDay()
return ds.sort(function(a,b){
return (days[a] < today ? days[a] + 7 : days[a])
- (days[b] < today ? days[b] + 7 : days[b])
})
}
【讨论】：
如果您有一个以一天为键的对象数组，您可以使用此版本的@SheetJS 答案
const sortDays = (days, timezone) => {
const dayOfWeek = 6;
const list = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'];
const sortedList = list.slice(dayOfWeek).concat(list.slice(0, dayOfWeek));
return days.sort((a, b) => {
if (sortedList.indexOf(a.day) > sortedList.indexOf(b.day)) return 1;
if (sortedList.indexOf(a.day) < sortedList.indexOf(b.day)) return -1;
return 0;
});
};
const days = [
{"_id":"Z378zCrqGM5XNbsXK","color":"#F47373","day":"Friday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"SY83MsxwEyKYrZvxx","color":"#ea5030","day":"Friday","hour":12,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"Cy4SwenuDJqsSu8Wd","color":"#5a9830","day":"Friday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"MDboigebEAokYiuJv","color":"#F47373","day":"Monday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"PzhT93JKkJSbmuLqc","color":"#5a9830","day":"Monday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"kNuPToeSoJ3j8d6wW","color":"#F47373","day":"Saturday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"44NrPF8byhktY3w4K","color":"#5a9830","day":"Saturday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"BxwYYBKPWWEodtkbs","color":"#F47373","day":"Sunday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"9kHsucTj9JZJtyxos","color":"#37D67A","day":"Sunday","hour":9,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"5fz3tAHfHARiafuBg","color":"#ea5030","day":"Sunday","hour":12,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"ZeC8Y8YLGKrK7q3g7","color":"#5a9830","day":"Sunday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"vHjA9hcfLPCp3CBQQ","color":"#F47373","day":"Thursday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"Fmd4xccrPHqDyrhRx","color":"#37D67A","day":"Thursday","hour":8,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"Zijtdb8Cv68cPBc3L","color":"#ea5030","day":"Thursday","hour":12,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"yDf5tj3NQCZXT3iWa","color":"#5a9830","day":"Thursday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"ve9vuxcb6ZkLZgfFq","color":"#F47373","day":"Tuesday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"s5mbpz9oyzjtzXwCt","color":"#0f5b30","day":"Tuesday","hour":21,"minute":23,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"aXZSoJ3cQiA9Hocwa","color":"#5a9830","day":"Tuesday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"FqqaRBPKd3RjHzQEz","color":"#F47373","day":"Wednesday","hour":7,"minute":45,"workspaceId":"6oaKfaAc7GhGYohA9"},{"_id":"e8A5LACfXYfGtacJA","color":"#5a9830","day":"Wednesday","hour":22,"minute":53,"workspaceId":"6oaKfaAc7GhGYohA9"}]
console.log(sortDays(days));【讨论】：
如果您想从“星期一”开始排序，这就是我的答案。您可以通过更改
daySort变量值来更改开始日期。你只需要给这个方法一个未排序的工作日数组，它就会对其进行排序。
sortDays(unsortedDays) {
let daysSort = ['monday', 'tuesday', 'wednesday', 'thursday', 'friday',
'satuday', 'sunday'];
let sortedDays = [];
daysSort.forEach((value) => {
if (unsortedDays.includes(value)) {
sortedDays.push(value);
}
});
return sortedDays;
}
【讨论】：